earth@work wrote:thanks, mod confuses me!
i did not take square of both the sides - could someone help me understand where i was going wrong in my method:
lx + 1l = 2lx - 1l
i took 2 conditions either x s negative or x is positive
when x is negative: -x+1 = 2(-x-1) ==> x= -3
when x is positive: x+1 = 2(x-1) ==> x=3
and in both the case lxl >1
i know i m making a mistake somewhere but not able to figure out what? Help needed!
If you put x=-3 in the original equation you get,
|-3+1|=2|-3-1|
2=8
Therefore x=-3 is not a solution.
You didn't consider the case where 0<x<1
x+1 = -2(x-1)
x=1/3
if x >1
x+1 =2(x-1)
x=3 but according to STMT2 this is not true
so x=1/3
