Roland2rule wrote:Ann, Mark, Dave and Paula line up at a ticket window. In how many ways can they arrange themselves so that Dave is third in line from the window?
a 24
b 12
c 9
d 6
e 3
Number of options for the third position = 1. (Must be Dave.)
Number of ways to arrange the remaining 3 people = 3!.
To combine the options above, we multiply:
1*3! = 6.
The correct answer is
D.
Most of the answer choices are quite small, implying that we can simply list all of the arrangements in which D is in the third position:
AM
DP
AP
DM
MA
DP
MP
DA
PA
DM
PM
DA.
Total ways = 6.
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