ziyuenlau wrote:What is the remainder when 5-digit positive integer pqpqp is divided by 3?
(1) p=2
(2) q=3
Source : Math Revolution
Statement 1: p = 2
This number is 2q2q2
For a number to be completely divisible by '3', the sum of its digits must be divisible by '3,' else we get a remainder.
Sum of digits = 2+q+2+q+ = 6 + 2q
We see that '6' is divisible by '3', and the remainder of '2q' divisible by '3' would depend on the value of 'q'. You may try any value for q from 0,1,2,...9. The remainders are not the same for the chosen digits. Insufficient.
Statement 2: q = 3
This number is p3p3p
Sum of digits = p+3+p+3+p = 6 + 3p = 3(2 + p).
Since 3(2 + p) is a factor of '3,' it is completely divisible by '3,' leaving a remainder '0.' The value of q does not affect the remainder. Sufficient.
The correct answer:
B
Hope this helps!
Relevant book:
Manhattan Review GMAT Math Essentials Guide
-Jay
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