At an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 25% of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?
A.15%
B. 20%
C. 25%
D. 30%
E. 40%
Answer: B
Source: Veritas Prep
At an elite baseball camp, 60% of players can bat both right-handed
This topic has expert replies
-
- Legendary Member
- Posts: 1223
- Joined: Sat Feb 15, 2020 2:23 pm
- Followed by:1 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
GMAT/MBA Expert
- Jay@ManhattanReview
- GMAT Instructor
- Posts: 3008
- Joined: Mon Aug 22, 2016 6:19 am
- Location: Grand Central / New York
- Thanked: 470 times
- Followed by:34 members
SayBTGModeratorVI wrote: ↑Thu Jul 23, 2020 6:49 amAt an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 25% of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?
A.15%
B. 20%
C. 25%
D. 30%
E. 40%
Answer: B
Source: Veritas Prep
R = No. of players who ONLY bat right-handed;
L = No. of players who ONLY bat left-handed;
B = No. of players who bat both right- and left-handed = 60%;
From the information, "25% of the players who bat left-handed do not bat right-handed," we know that
25% of (L + B) = L
(L + 60)/4 = L
L = 20%
Thus, R = 100 – 20 – 60 = 20%
Correct answer: B
Hope this helps!
-Jay
_________________
Manhattan Review GMAT Prep
Locations: GMAT Prep Minneapolis | GRE Prep Irvine | LSAT Prep Chicago | SAT Prep Washington DC | and many more...
Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
-
- Junior | Next Rank: 30 Posts
- Posts: 17
- Joined: Fri Jul 24, 2020 11:07 am
- Location: INDIA
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7294
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
Solution:BTGModeratorVI wrote: ↑Thu Jul 23, 2020 6:49 amAt an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 25% of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?
A.15%
B. 20%
C. 25%
D. 30%
E. 40%
Answer: B
We can let the total number of players = 100. So we have 60 players who can bat both right-handed and left-handed. We can let x = the number of players who can only bat left-handed. Thus, 40 - x = the number of players who can only bat right handed. We are given that 25% of the players who bat left-handed do not bat right-handed, which means they can only bat left-handed. Therefore, we can create the equation:
0.25(x + 60) = x
x + 60 = 4x
60 = 3x
20 = x
So we have 20 players who can only bat left-handed and also 40 - 20 = 20 players who can only bat right handed. We are asked for the probability that a player selected at random does not bat left-handed, i.e., who can only bat right-handed. Therefore, that probability is 20/100 = 20%.
Answer: B
Scott Woodbury-Stewart
Founder and CEO
[email protected]
![Image](https://www.beatthegmat.com/mba/uploads/images/partners/target_test_prep/TTPsig2022.png)
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
![Image](https://manticoreaudio.com/wp-content/uploads/2017/07/37px-email.png)
![Image](https://manticoreaudio.com/wp-content/uploads/2017/07/37px-linked.png)
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
We can solve using the Double Matrix Method.BTGModeratorVI wrote: ↑Thu Jul 23, 2020 6:49 amAt an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 25% of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?
A.15%
B. 20%
C. 25%
D. 30%
E. 40%
Answer: B
Source: Veritas Prep
The Double Matrix Method can be used for most questions featuring a population in which each member has two characteristics associated with it.
Here, we have a population of baseball players, and the two characteristics are:
- bats left-handed or DOESN'T bat left-handed
- bats right-handed or DOESN'T bat right-handed
NOTICE that the question does not ask us to find an actual number. It asks us to find a probability. This means we can assign whatever value we wish to the total number of couples.
So, let's say there are 100 players, which we'll add to our diagram:
![Image](https://s2.postimg.cc/h159hmgz9/bb1.jpg)
60% of players can bat both right-handed and left-handed
60% of 100 = 60, so 60 players can bat both right-handed AND left-handed .
Add that to the diagram to get:
![Image](https://s2.postimg.cc/s3acg2b1x/bb2.jpg)
25% of the players who bat left-handed do not bat right-handed
Hmmm, we don't know the number of left-handed players, so we can't find 25% of that value.
So, let's assign a variable.
Let's let x = left-handed batters, and add it to our diagram:
![Image](https://s2.postimg.cc/j6zkc4kfp/bb3.jpg)
So, x of the 100 players bat left handed.
25% of the players who bat left-handed do not bat right-handed
If x players bat left-handed, then 25% of x do not bat right-handed.
In other words, 0.25x = number of players who do not bat right-handed
Add this to our diagram:
![Image](https://s7.postimg.cc/l3mmnxpk7/bb4.jpg)
At this point, we see that the two left-hand boxes add to x.
So, we can write the equation: 60 + 0.25x = x
Rearrange to get 60 = 0.75x
Rewrite 0.75 as fraction to get: 60 = (3/4)x
Multiply both sides by 4/3 to get: 80 = x
If x = 80, then we know that 80 of the 100 players bat left-handed.
This means that the remaining 20 players DO NOT bat left handed.
![Image](https://s2.postimg.cc/gs7orp46t/bb5.jpg)
So, P(player doesn't bat left-handed) = 20/100 = 20%
Answer: B
This question type is VERY COMMON on the GMAT, so be sure to master the technique.
To learn more about the Double Matrix Method, watch this video: https://www.gmatprepnow.com/module/gmat- ... ems?id=919
Once you’re familiar with this technique, you can attempt these additional practice questions:
Easy Problem Solving questions
- https://www.beatthegmat.com/finance-majo ... 67425.html
Medium Problem Solving questions
- https://www.gmatprepnow.com/module/gmat- ... /video/920
- https://www.beatthegmat.com/posted-speed ... 72374.html
- https://www.beatthegmat.com/motel-t271938.html
- https://www.beatthegmat.com/of-the-appli ... 70255.html
- https://www.beatthegmat.com/opening-nigh ... 64869.html
- https://www.beatthegmat.com/at-least-100 ... 74669.html
- https://www.beatthegmat.com/prblem-solving-t279424.html
Difficult Problem Solving questions
- https://www.gmatprepnow.com/module/gmat- ... /video/946
- https://www.beatthegmat.com/ratio-problem-t268339.html
- https://www.beatthegmat.com/overlapping- ... 65223.html
- https://www.beatthegmat.com/fractions-t264254.html
- https://www.beatthegmat.com/overlapping- ... 64092.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-2
Easy Data Sufficiency questions
- https://www.gmatprepnow.com/module/gmat- ... /video/943
- https://www.beatthegmat.com/for-what-per ... 70596.html
- https://www.beatthegmat.com/ds-quest-t187706.html
Medium Data Sufficiency questions
- https://www.beatthegmat.com/sets-matrix-ds-t271914.html
- https://www.beatthegmat.com/each-of-peop ... 71375.html
- https://www.beatthegmat.com/a-manufacturer-t270331.html
- https://www.beatthegmat.com/in-costume-f ... 69355.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-1
Difficult Data Sufficiency questions
- https://youtu.be/dsCeqF9Kbk8
- https://www.beatthegmat.com/double-set-m ... 71423.html
- https://youtu.be/dOZ9KM1m5Hs
- https://www.beatthegmat.com/sets-t269449.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-3
Cheers,
Brent