boomgoesthegmat wrote:Pumping alone at their respective constant rates, one inlet pipe fills an empty tank to 1/2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 6 hours. How many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?
A) 3.25
B) 3.6
C) 4.2
D) 4.4
E) 5.5
Let the tank = 18 liters.
Since the first pipe takes 3 hours to fill 1/2 of the 18-liter tank, the rate for the first pipe = w/r = (1/2 * 18)/3 = 3 liters per hour.
Since the second pipe takes 6 hours to fill 2/3 of the 18-liter tank, the rate for the second pipe = w/r = (2/3 * 18)/6 = 2 liters per hour.
Since the combined rate for the two pipes = 3+2 = 5 liters per hour, the time for the two pipes together to fill the tank = w/r = 18/5 = 3.6 hours.
The correct answer is
B.
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