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A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of

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by BTGmoderatorDC » Sun Oct 25, 2020 4:43 pm

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A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of sauce and various spices. If a total of 6 pounds of sauce and spices are used, how many pounds of beans are used?

A. 3
B. 6
C. 12
D. 18
E. 24


OA C

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Re: A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture

by Scott@TargetTestPrep » Sat Oct 31, 2020 2:16 pm
BTGmoderatorDC wrote: ↑
Sun Oct 25, 2020 4:43 pm
 A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of sauce and various spices. If a total of 6 pounds of sauce and spices are used, how many pounds of beans are used?

A. 3
B. 6
C. 12
D. 18
E. 24


OA C

Solution:

We see that the recipe calls for 1 - 1/2 - 1/3 = 6/6 - 3/6 - 2/6 = 1/6 of the final mixture to consist of sauce and spices. If we let x = the number of pounds of beans that are needed, we can create the proportion: “x pounds of beans is to 1/3 as 6 pounds of sauces and spices is to 1/6.”

x / (1/3) = 6 / (1/6)

3x = 36

x = 12

Answer: C

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