Mean of the price of 3 houses = $120,000
Target question => What was the median price of the houses?
Statement 1 => The price of Tom's house was $110,000
Let Tom, Jane and Sue's price = x, y, and z respectively
$$\frac{x+y+z}{3}=$120,000$$
$$x+y+z=$360,000$$
According to the information in this statement; x=$110,000
Therefore, y + z = $360,000 - $110,000 = $250,000
To decide on the median, there are 3 possible scenarios to consider irrespective of the possible variation of y + z = $250,000
1st scenario => If y>z; assuming y = 150,000 and z = 100,000 then x, y, z = 110,000, 150,000, 100,000; median = x
2nd scenario => If y < z; assuming y = 120,000 and z = 130,000 then x, y, z = 110,000, 120,000, 130,000; median = y
3rd scenario => If y = z; assuming y = 125,000 and z = 125,000 then x, y, z = 110,000, 125,000, 125,000; median = y or z
The median is not definite and cannot answer the target question, statement 1 is NOT SUFFICIENT
Statement 2 =>The price of Jane's house was $120,000
Let Tom, Jane, and Sue's price = x, y, and z respectively
$$\frac{x+y+z}{3}=$120,000$$
$$x+y+z=360,000$$
y=$120,000; x + z = 360,000 - 120,000 = 240,000
If x > z; assuming x = 140,000 and z = 100,000 then x, y, z = 140,000, 120,000, 100,000; median = 120,000
If x < z; assuming x = 130,000 and z = 110,000 then x, y, z = 130,000, 120,000, 110,000; median = 120,000
If x = z assuming x = 120,000 and z = 120,000 then x, y, z = 120,000, 120,000, 120,000; median = 120,000
Statement 2 alone is SUFFICIENT
Answer = B
