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A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person

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A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person

by Vincen » Wed Jul 22, 2020 12:32 pm

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A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

[spoiler]OA=D[/spoiler]

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Re: A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person

by sahilaro23 » Fri Jul 24, 2020 11:48 am
First select 2 people out of a group of 4 in '4C2' says = 6 ways.

Now here the stewed can come first and then comes the treasurer, or vice versa also possible so multiply this by 2 = 6x2 = 12 total ways. Hence D.
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Re: A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person

by Scott@TargetTestPrep » Sat Jul 25, 2020 2:19 pm
Vincen wrote: ↑
Wed Jul 22, 2020 12:32 pm
 A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

[spoiler]OA=D[/spoiler]

Solution:

Since we have specific positions in the group, order matters, and so we have a permutation. Thus, the number of ways to select a steward and a treasurer from 4 employees is 4P2 = 4!/2! = 4 x 3 = 12 ways.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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