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Inference

by akash singhal » Mon Nov 16, 2015 1:46 am
In Patton City, days are categorized as having heavy rainfall (more than two inches),
moderate rainfall (more than one inch, but no more than two inches), light rainfall (at least a
trace, but no more than one inch), or no rainfall. In 1990, there were fewer days with light
rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the year was 20
percent higher in 1990 than in 1910. If the statements above are true, then it is also
possible that in Patton City

A. the number of days with heavy rainfall was lower in 1990 than in 1910
B. the number of days with some rainfall, but no more than two inches, was the same in 1990 as
in 1910
C. the number of days with some rainfall, but no more than two inches, was higher in 1990 than
in 1910
D. the total number of inches of rain that fell on days with moderate rainfall in 1990 was more
than twice what it had been in 1910
E. the average amount of rainfall per month was lower in 1990 than in 1910

Answer not given
I think its D

Can anyone clarify and explain the reasoning involved?
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by vishalwin » Mon Nov 16, 2015 1:17 pm
OA is A. Please check again.

h1- heavy rainfall in 1910
h2- heavy rainfall in 1990

m1- medium rainfall in 1910
m2- medium rainfall in 1910

l1- low rainfall in 1910
l2- low rainfall in 1910

1910- h1, m1, l1

1990- h2, m2, l2

h2<h1 & m2<m1 but overall rainfall in 1990 > overall rainfall in 1910

therefore l2 must be more than l1 to make overall rainfall in 1990 > overall rainfall in 1910.
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by akash singhal » Tue Nov 17, 2015 6:20 am
vishalwin wrote:OA is A. Please check again.

h1- heavy rainfall in 1910
h2- heavy rainfall in 1990

m1- medium rainfall in 1910
m2- medium rainfall in 1910

l1- low rainfall in 1910
l2- low rainfall in 1910

1910- h1, m1, l1

1990- h2, m2, l2

h2<h1 & m2<m1 but overall rainfall in 1990 > overall rainfall in 1910

therefore l2 must be more than l1 to make overall rainfall in 1990 > overall rainfall in 1910.

hey,
You understood the question wrong.
its given
l2<l1 & m2<m1

A says h2<h1 not necessarily true(Since no. of heavy rainfall days can be more not the amount of rainfall).Your deduction should say h2>h1 even then A is wrong
I cant find the answer or the explanation that's why posted here...

check again
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by DavidG@VeritasPrep » Tue Nov 17, 2015 6:59 am
akash singhal wrote:In Patton City, days are categorized as having heavy rainfall (more than two inches),
moderate rainfall (more than one inch, but no more than two inches), light rainfall (at least a
trace, but no more than one inch), or no rainfall. In 1990, there were fewer days with light
rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the year was 20
percent higher in 1990 than in 1910. If the statements above are true, then it is also
possible that in Patton City

A. the number of days with heavy rainfall was lower in 1990 than in 1910
B. the number of days with some rainfall, but no more than two inches, was the same in 1990 as
in 1910
C. the number of days with some rainfall, but no more than two inches, was higher in 1990 than
in 1910
D. the total number of inches of rain that fell on days with moderate rainfall in 1990 was more
than twice what it had been in 1910
E. the average amount of rainfall per month was lower in 1990 than in 1910

Answer not given
I think its D

Can anyone clarify and explain the reasoning involved?
Odd question. Take a very simple concrete scenario. Say in 1910, we have the following:

1 Day Light rain: (trace amounts)
1 Day Moderate rain: (2 inches)
2 Days Heavy rain: (4 inches each, for a total of 8 inches)
Total rain in 1910: about 10 inches

In 1990, we'll have fewer days of light and moderate rain, but 20% more total rain. So you could have the following:
1 Day Heavy rain: 12 inches

The question asks which is possible. Well, it's clearly possible that you have fewer days of heavy rain in 1990 - in our example above, we have 1 day of heavy rain in 1990 and 2 days of heavy rain in 1910. So A works.
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