Aristotle # 5

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 164
Joined: Tue May 12, 2015 9:06 am
Thanked: 3 times

Aristotle # 5

by oquiella » Sat Oct 24, 2015 10:47 am
5. Five people - Adam, Bob, Craig, Daniel and Evan - are of different ages. Daniel is
younger than both Adam and Craig. Craig is younger than Bob but older than Evan.
Who among the five is the oldest?


(1) The average age of Adam and Bob is less than the average age of Craig and
Evan.
(2) The average age of Bob and Craig is less than the average age of Adam and
Evan.


PLEASE EXPLAIN. BREAK IT DOWN
Source: — Data Sufficiency |

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Sat Oct 24, 2015 11:16 am
oquiella wrote:5. Five people - Adam, Bob, Craig, Daniel and Evan - are of different ages. Daniel is
younger than both Adam and Craig. Craig is younger than Bob but older than Evan.
Who among the five is the oldest?

(1) The average age of Adam and Bob is less than the average age of Craig and
Evan.
(2) The average age of Bob and Craig is less than the average age of Adam and
Evan.
From the prompt:
D < A and D < C.
E < C < B.

Statement 1: The average age of Adam and Bob is less than the average age of Craig and Evan.
(A+B)/2 < (C+E)/2
A+B < C+E.

Adding together A+B < C+E and C < B, we get:
(A+B) + C < (C+E) + B
A < E.

Linking together D < A, A < E and E < C < B, we get:
D < A < E < C < B.
B is the oldest.
SUFFICIENT.

Statement 2: The average age of Bob and Craig is less than the average age of Adam and Evan.
(B+C)/2 < (A+E)/2
B+C < A+E.

Adding together B+C < A+E and E < C, we get:
(B+C) + E < (A+E) + C
B < A.

Linking together E < C < B and B < A, we get:
E < C < B < A.
Since D < A, A is the oldest.
SUFFICIENT.

Whereas B is the oldest in statement 1, A is the oldest in statement 2.
This problem is FLAWED.
On the GMAT, the two statements CANNOT contradict each other.
I would ignore this problem.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Master | Next Rank: 500 Posts
Posts: 164
Joined: Tue May 12, 2015 9:06 am
Thanked: 3 times

by oquiella » Mon Oct 26, 2015 1:50 pm
GMATGuruNY wrote:
oquiella wrote:5. Five people - Adam, Bob, Craig, Daniel and Evan - are of different ages. Daniel is
younger than both Adam and Craig. Craig is younger than Bob but older than Evan.
Who among the five is the oldest?

(1) The average age of Adam and Bob is less than the average age of Craig and
Evan.
(2) The average age of Bob and Craig is less than the average age of Adam and
Evan.
From the prompt:
D < A and D < C.
E < C < B.

Statement 1: The average age of Adam and Bob is less than the average age of Craig and Evan.
(A+B)/2 < (C+E)/2
A+B < C+E.

Adding together A+B < C+E and C < B, we get:
(A+B) + C < (C+E) + B
A < E.

Linking together D < A, A < E and E < C < B, we get:
D < A < E < C < B.
B is the oldest.
SUFFICIENT.

Statement 2: The average age of Bob and Craig is less than the average age of Adam and Evan.
(B+C)/2 < (A+E)/2
B+C < A+E.

Adding together B+C < A+E and E < C, we get:
(B+C) + E < (A+E) + C
B < A.

Linking together E < C < B and B < A, we get:
E < C < B < A.
Since D < A, A is the oldest.
SUFFICIENT.

Whereas B is the oldest in statement 1, A is the oldest in statement 2.
This problem is FLAWED.
On the GMAT, the two statements CANNOT contradict each other.
I would ignore this problem.


I've never seen this approach Why did you add the given inequalities? Can you give me another problem you've seen that has the same approach?

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Mon Oct 26, 2015 2:29 pm
oquiella wrote: I've never seen this approach Why did you add the given inequalities? Can you give me another problem you've seen that has the same approach?
From the prompt:
D < A
D < C
E < C < B.
Given these relationships, only A or B can be the oldest.

Statement 1:
A+B < C+E
C < B.
I added these inequalities because I could see that the values in red would cancel out, allowing me to determine the relationship between A and E, as shown in my post above.

Statement 2:
B+C < A+E
E < C.
I added these inequalities because I could see that the values in blue would cancel out, allowing me to determine the relationship between B and A, as shown in my post above.

Other problems that can be solved by adding together two inequalities:
https://www.beatthegmat.com/can-i-use-te ... 78286.html
https://www.beatthegmat.com/is-z-between ... 70021.html
https://www.beatthegmat.com/for-the-stud ... 65203.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3