BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Ayayai, iMe, iMine et al

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 156
Joined: Sun Jul 15, 2012 12:03 pm
Location: New York, USA
Thanked: 34 times
Followed by:1 members

Ayayai, iMe, iMine et al

by kartikshah » Sun Jul 22, 2012 5:55 am
Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

1. 24k
2. 25k
3. 26k
4. 27k
5. 28k

Source: Master GMAT

Open to all who'd like to try. OA to be announced shortly ;-)
Top
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 210
Joined: Thu Mar 08, 2012 11:24 pm
Thanked: 62 times
Followed by:3 members

by niketdoshi123 » Sun Jul 22, 2012 6:45 am
kartikshah wrote:Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

1. 24k
2. 25k
3. 26k
4. 27k
5. 28k
Given "Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month"
=> 8000+x+y1 = 21000
=> x+y1 = 13000 -----(1)
From the figure below
x+y2 = 11000 -----(2)
and y1+y2 = 12000 -----(3)

Subtracting (2) from (3)
y1-x = 1000 -----(4)

adding (1) and (4)
2y1 = 14000
=> y1 = 7000

=> z1 = 8000+7000 = 15000
=> [spoiler]z = 15000 + 11000 = 26k[/spoiler]
Hence the correct answer is 3
Attachments
os.jpg
Top
User avatar
Legendary Member
Posts: 520
Joined: Sat Apr 28, 2012 9:12 pm
Thanked: 339 times
Followed by:49 members
GMAT Score:770

by eagleeye » Sun Jul 22, 2012 7:07 am
kartikshah wrote:Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

1. 24k
2. 25k
3. 26k
4. 27k
5. 28k

Source: Master GMAT

Open to all who'd like to try. OA to be announced shortly ;-)
Typically you could do those questions by using venn diagrams.
However, we could just use the union of two sets here.
We need to find the total. We are given the data regarding OLED screens and Imine models. Let's use those. (I have disregarded the 1000 factor to make the calculations elegant)

Total = OLED + IMine - (Both OLED and iMine) + (Neither OLED, Nor Imine)
Now Neither OLED, Nor iMine = iMe LCD
Then Total= 11 + 12 -(OLED iMine) + (iMe LCDs) = 11+12 - (OLED iMines) + 8 = 31-OLED iMine
We are told that Total - OLED iMine = 21.

Then equating the two, we get 21 + OLED iMine = 31 - OLED iMine
=> OLED Imine = (31-21)/2 = 5.

Hence Total = 21 + OLED iMine = 21 + 5 = 26.

Hence [spoiler]C = 26k[/spoiler] is correct.
Top
Post new topic Post Reply
• Page 1 of 1