[email protected] wrote:Well I do not know how am I not getting the answer as A. I am getting the answer as E.
watever explanation u have given i read those but i have a doubt in this question...
answer is
A
-8<y<0, Question: Is 2x>y-8?
st(1) implies distance between x and -8 is shorter than the distance between x and y OR |x-(-8)|<|x-y|, Tip~ mode is convenient for measuring distance between the numbers on the number line.
|x+8|<|x-y|, Solve by squaring both sides, this will be quicker. x^2+16x+64<x^2-2xy+y^2, y^2-2xy-16x-64>0, y^2-2x(y+8)-64>0, (y^2-64)/(y+8)>2x, (y-8)(y+8)/(y+8)>2x, y-8>2x Sufficient to answer No
st(2) provides x=4y and by multiplying both sides by 2 we get 2x=8y. From the question we know -8<y<0 and for example two cases considered:
case a) y=-1, x=-4 and to answer the question 2x>y-8 we test -8>-1-8, Yes
case b) y=-7, x=-28 and test 2x>y-8 returns -56>-7-8, No
Not Sufficient.
~Tip, you can directly answer st(2) Not Sufficient as x=4y implies literally x and y can be everything and contradicts our question's constraint -8<x<0
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