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Probability models

Expert replies
by Tryingmybest » Wed Mar 25, 2009 5:50 am
Out of seven models, all of different heights, five models will be chosen to pose for a photograph. If the five models are to stand in a line from shortest to tallest, and the fourth-tallest and sixth-tallest models cannot be adjacent, how many different arrangements of five models are possible?

6
11
17
72
210

OA D
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Source: — Problem Solving |

by krisraam » Wed Mar 25, 2009 8:31 pm
No of ways of selecting = 7C2 = 21.

Arrangement is always 1.

No of ways of selecting 4th and 6th and not selecting 5th =
2C2(From 4 and 6) * 4C3( Excluding 5 so the selection is from 4) = 4

21 -4 = 17

Thanks
Raama
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