Cos problem says k = 5.1 * 10 ^ n. This is positive right?

But otherwise , if k^2 = 25 is stated , then can k be positive as well as negative ?

k = 5.1 × 10^n means k is positive, as the right-hand-side (RHS) is positive. Find k-?

st(1) 6,000 < k < 500,000 can be rewritten as 6*10^3 < k < 5 *10^5. If we compare the left-hand-side (LHS) and RHS we notice that 6>5.1 BUT 5.1>5. We should deduce about 3<n<5 in expression 10^n. Because n is a positive integer n=4, Statement (1) gives us k=5.1*10^4 Sufficient

st(2) k^2 = 2.601 × 109 by using the question information can be rewritten as 26.01 × 100^n = 2.601 × 109 (remember LHS is k^2, so we need to multiply our result by 2 for k^1 OR k); It's easy to notice that n is slight more than 2 for the equality 26.01 × 100^n = 2.601 × 109 be valid, BUT we need to multiply by factor 2 and n=4. Statement (2) gives us k=5.1 *10^4 Sufficient;

answer is D (cleared the previous query)

mundasingh123 wrote:151. If n is a positive integer and k = 5.1 × 10^n, what is the
value of k ?
(1) 6,000 < k < 500,000
(2) k^2 = 2.601 × 109
Why is answer D.
In option 2

(2) k^2 = 2.601 × 109

, k can be positive or negative