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then a =

by sanju09 » Tue Aug 10, 2010 3:56 am
If a + b - c = d, and if a - b + c = e, then a =
(A) d + e
(B) 2 d + e
(C) ½ (d + e)
(D) 2 (d + e)
(E) d - e

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by selango » Tue Aug 10, 2010 4:05 am
a+b-c=d-->eqn1

a-b+c=e

a-(b-c)=e

From eqn1,b-c=d-a

a-(d-a)=e

a-d+a=e

a=(d+e)/2 or 1/2(d+e)

Pick C
Last edited by selango on Tue Aug 10, 2010 4:25 am, edited 1 time in total.
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by sanju09 » Tue Aug 10, 2010 4:24 am
selango wrote:a+b-c=d-->eqn1

a-b+c=e

a-(b-c)=e

From eqn1,b-c=d-a

a-(d-a)=e

a-d+a=e

a=d+e/2

Pick C
The line in bold could confuse many, as this is mathematically not same as

[spoiler](C) ½ (d + e)[/spoiler]
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by likithae » Wed Aug 11, 2010 1:33 am
selango wrote:a+b-c=d-->eqn1

a-b+c=e

a-(b-c)=e

From eqn1,b-c=d-a

a-(d-a)=e

a-d+a=e

a=(d+e)/2 or 1/2(d+e)

Pick C
thank you .....can you explain me little bit clear....
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