Sukhman is OA C,sukhman wrote:1^1+2^2+3^3+----10^10 is divided by 5 . What is the remainder?
a. 0 b.1 c.2 d.3 e.4
Here is how I did,
Anything to the power of 1 end in =================1
2^2 =================4
3^3 =================7(3,9,7,1)
4^4 =================6(series go like this, 4,6, same again)
5^5 =================5
6^6 =================6
7^7 =================3(7,9,3,1)
8^8 =================6(8,4,2,6)
9^9 =================9(9,1)
10^10 =================0
Sum ends in 7
So OA is 2
