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by GMATGuruNY » Fri Mar 04, 2016 5:54 am
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a certain amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?

a. 3/10
b. 2/5
c. 1/2
d. 2/3
e. 6/5
Let x = the yearly increase.
Height after 4 years = 4 + 4x.
Height after 6 years = 4 + 6x.

At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year.
The phrase in red implies the following:
The height in the 6th year was 6/5 of the height in the 4th year.
An equivalent statement:
At the end of the 6th year, the tree was 20% taller than it was at the end of the 4th year.
Here, the phrase in red implies the following:
The height in the 6th year was 120% of the height in the 4th year.

Since the height in the 6th year was 6/5 of the height in the 4th year, we get:
(4 + 6x) = (6/5)(4 + 4x)
20 + 30x = 24 + 24x
6x = 4
x = 4/6 = 2/3.

The correct answer is D.

An alternate approach is to plug in the answers, which represent the increase each year.
When the correct answer choice is plugged in, (6th-year height)/(4th-year height) = 6/5.

Answer choice D: 2/3
Height after 4 years = 4 + 4(2/3) = 20/3.
Height after 2 more years = 20/3 + 2(2/3) = 24/3.
(6th-year height)/(4th-year height) = (24/3) / (20/3) = 24/20 = 6/5.
Success!

The correct answer is D.
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by Brent@GMATPrepNow » Fri Mar 04, 2016 7:37 am
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a certain amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?

A. 3/10
B. 2/5
C. 1/2
D. 2/3
E. 6/5
Height of tree on day 0 = 4
Let d = the height increase each year
Height of tree at the end of the 1st year = 4+d
Height of tree at the end of the 2nd year = 4+d+d = 4 + 2d
Height of tree at the end of the 3rd year = 4+d+d+d = 4 + 3d
Height of tree at the end of the 4th year = 4+d+d+d+d = 4 + 4d
Height of tree at the end of the 5th year = 4+d+d+d+d+d = 4 + 5d
Height of tree at the end of the 6th year = 4+d+d+d+d+d+d = 4 + 6d

At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year
In other words, 6th year height = 4th year height + 1/5(4th year height)
Or we can write 4 + 6d = (4 + 4d) + 1/5(4 + 4d)
Simplify: 4 + 6d = 6/5(4 + 4d)
Multiply both sides by 5 to get: 5(4 + 6d) = 6(4 + 4d)
Expand: 20 + 30d = 24 + 24d
Simplify: 6d = 4
d = 4/6 = [spoiler]2/3[/spoiler] = D

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by [email protected] » Fri Mar 04, 2016 9:41 am
Hi eitijan,,

TESTing the ANSWERS is a great way to tackle this question. The "fast" way to solve a problem can still sometimes take time, but regardless of how you approach a prompt, you still need to take notes and stay organized.

From the screen capture, you chose answer C (1/2). If you jot down some quick notes, here's what you'd have:

Start = 4 ft
Yr. 1 = 4 1/2
Yr. 2 = 5
Yr. 3 = 5 1/2
Yr. 4 = 6
Yr. 5 = 6 1/2
Yr. 6 = 7

It doesn't make much time/effort to take these notes. Now, compare Year 6 to Year 4....Is it 1/5 greater? 7 to 6 is 1/6 greater, so answer C is not what we're looking for. It also gives us a "nudge" in the right direction. We need a 1/5 increase, but we only have a 1/6 increase right now....so we need a bigger increase.....so we need a bigger absolute increase each year. The correct answer has to be D or E.

Looking at all 5 choices as a group, I'm pretty sure the answer is D, but we can certainly prove it...

Start = 4 ft
Yr. 1 = 4 2/3
Yr. 2 = 5 1/3
Yr. 3 = 6
Yr. 4 = 6 2/3
Yr. 5 = 7 1/3
Yr. 6 = 8

This comparison requires a bit more math, but isn't "crazy" by any definition.

6 2/3 = 20/3
8 = 24/3

Ignore the denominators....24 to 20..... 1/5 of 20 = 4.....24 IS 1/5 greater than 20.

Final Answer: D

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by Matt@VeritasPrep » Fri Mar 04, 2016 3:28 pm
Suppose the tree increases x each year. We know that

(4 + six increases) = (1 + 1/5) * (4 + four increases)

Writing it out in words makes it easier to follow! Now we'll call the increase each year x, and write

4 + 6x = (1 + 1/5) * (4 + 4x)

4 + 6x = (6/5) * (4 + 4x)

4 + 6x = 24/5 + (24/5)x

(6/5)x = 4/5

x = 2/3

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by eitijan » Sat Mar 05, 2016 2:02 am
Thank you everyone.
I loved the way Rich solved it.
Thanks again. :)

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by [email protected] » Sat Mar 05, 2016 5:28 pm
Hi eitijan,

As an approach, TESTing THE ANSWERS will be useful on a few questions on Test Day, so it's worth practicing during your studies. Remember that nobody will care how you got the correct answer to any of the questions that you face on Test Day, so you should train in Tactics and methods beyond just pure mathematical approaches (which can sometimes be overly complex and time-consuming).

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by eitijan » Sat Mar 05, 2016 9:09 pm
Yes, Practicing is the key.
Could you please suggest me from where I should practice besides Official guide.

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by [email protected] » Sat Mar 05, 2016 11:23 pm
Hi eitijan,

You ask a rather broad question, so I suggest that you repost it here:

https://www.beatthegmat.com/gmat-strategy-f3.html

In that way, we can focus on that area (and not the singular Quant prompt that we're currently on).

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by Matt@VeritasPrep » Thu Mar 17, 2016 8:48 pm
eitijan wrote:Yes, Practicing is the key.
Could you please suggest me from where I should practice besides Official guide.
We've got a great question bank full of free questions as well, definitely worth checking out.