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gmattesttaker2
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Hello,
Can you please assist with this:
Quick Sell Outlet sold a total for 40 televisions, each of which was either a Model P TV or A Model Q TV. Each Model P sold for $p and each model Q sold for $q. The average selling price of the 40 televisions was $141. How many of the 40 televisions were Model P Televisions?
1 - Model P sold for $30 less than the Model Q Televisions
2 - Either p = 120 or q = 120.
OA: C
I tried to solve as follows:
Let the number of model P TV's sold = x
Let the number of model Q TV's sold = y
Given, 40 = x + y - Eq. 1
Average Selling price = 141
=> 141 = x($p) + y($q) / 40
=> xp + yq = 5640 - Eq. 2
To determine: x = ?
1) p = q - 30 - Insuff.
2) p = 120 or q = 120 - Insuff.
1 and 2:
p = 120 = > 120 = q - 30 => q = 150
q = 120 => p = 120 - 30 => p = 90
At this point I got stuck though. Can you please help with this?
Thanks,
Sri
Can you please assist with this:
Quick Sell Outlet sold a total for 40 televisions, each of which was either a Model P TV or A Model Q TV. Each Model P sold for $p and each model Q sold for $q. The average selling price of the 40 televisions was $141. How many of the 40 televisions were Model P Televisions?
1 - Model P sold for $30 less than the Model Q Televisions
2 - Either p = 120 or q = 120.
OA: C
I tried to solve as follows:
Let the number of model P TV's sold = x
Let the number of model Q TV's sold = y
Given, 40 = x + y - Eq. 1
Average Selling price = 141
=> 141 = x($p) + y($q) / 40
=> xp + yq = 5640 - Eq. 2
To determine: x = ?
1) p = q - 30 - Insuff.
2) p = 120 or q = 120 - Insuff.
1 and 2:
p = 120 = > 120 = q - 30 => q = 150
q = 120 => p = 120 - 30 => p = 90
At this point I got stuck though. Can you please help with this?
Thanks,
Sri

















