Are x and y both positive? (GMATPrep)

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Are x and y both positive? (GMATPrep)

by clawhammer » Sat Nov 27, 2010 3:29 am
For this question (attached), I first assumed x=1/4, y=-1/4; then x=1. y =1/2.
Somehow I find both to satisfy the statements. Please help me find where I am getting it wrong. :(

Image

I simplified the equations as:

x-y = 1/2

x>y

Somewhere I'm getting it wrong!

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by beat_gmat_09 » Sat Nov 27, 2010 4:19 am
statement 1 simplification is correct. (x-y) = 1/2
For statement 2 remember when you are not given about the sign of variables you can multiply them in inequalities, but you have to consider +ve and -ve cases.
you only considered +ve case.
x/y*y > 1*y this is true when y is +ve, for this statement both the statements have to be considered, y<0 and y>0
when y is -ve :

x/(y) * (y) < (1) (y) ........ note the inequality sign has to be changed.
x < y ...... x is negative as x is less than -y
both statements are not sufficient.

Combining 1 & 2
x-y=1/2 and from statement 2 you know that x > y (both are positive as y is positive in this case) and x < y (both are negative as y is negative in this case)
case 1 - x and y both positive.
from statement 1, x - y =1/2 , this will hold true as x>y , no need to plug numbers.
case 2 - x and y both negative.
from statement 1, x - y =1/2, in this case x < y the difference cannot be +ve hence this is not true. Discard y -ve and x -ve case. Case 1 remains, x and y both are +ve.

Thus 1 & 2 are sufficient.
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by goyalsau » Sat Nov 27, 2010 4:27 am
I ) x - y = 1/2

If we assume x = 1/4 , y = - 1/4 Answer will be 1/2 (as you say ) { one is positive and another one is negative }

If we assume x = 3/2 y = 2/2 Answer will be 1/2 (as you say ) { Both are positive }

In sufficient

II ) X/Y > 1

Either Both are positive or Both Negative & X should always be Greater then Y

We can re write it as X > Y

Again put the same values in both the cases x > y ,

In sufficient,

Now Combining Both statements,

x - y = 1/2 { Regardless of sign Absolute value of x is greater than y Because sign will cancel out, }

Considering +ve sign First,

For any value of X which is higher than the value of Y , X - Y will always we positive,

Considering -ve sign ( Consider Absolute values )

For any -ve value of X if we add any thing which is smaller than X result will always be -ve
Like -3/4 + 1/4 = -2/4 WE are adding Because x - y
-7/8 + 6/8 = -1/8

So the result will always be - ve Hence for x-y to be +ve Both x and y should be +ve
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by clawhammer » Sat Nov 27, 2010 5:14 am
Thanks a lot guys. You all make complete sense. I wish I could be good at digging deep fast enough under time pressure.

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by Rahul@gurome » Sat Nov 27, 2010 5:20 am
Though goyalsau and beat_gmat_09 provided effective and easy solution to the question, I want to provide some insight into the question. Picking numbers and cross checking the statements is a very common strategy to attack GMAT problems. But don't practice them directly. If you are going for that method then you've to choose the numbers carefully! My suggestion is: First go through the basics, Strengthen your concepts and then go for the shortcuts. If your concepts are clear, you'll never make a wrong assumption.

Statement 1: 2x - 2y = 1
Implies (x - y) = 1/2. This means the only case that is not possible is x negative and y positive. In that case the LHS will be negative always! So the possible cases are (with examples),
  • (1) x positive, y positive (x = 4.5, y = 4)
    (2) x positive, y negative (x = 0.25, y = -0.25)
    (3) x = 0.5, y = 0
    (4) x = 0 , y = -0.5
    (5) x negative, y negative (x = -4, y = -4.5)
(Note : In each case there is also some constraints. Like in the 1st case, not for all positive x, y the relation will hold! x must be equal to (y + 0.5) etc.)

Not sufficient.

Statement 2: (x/y) > 1
Again this implies any one of the following two cases,
  • (1) Both of them are positive and x > y
    (2) Both of them are negative and x < y
Not sufficient.

1 & 2 Together: Statement 2 limits the number of possible cases to two. Let's analyze them again with the help of statement 1.
  • (1) Both of them are positive and x > y => (x - y) = 0.5 is possible.
    (2) Both of them are negative and x < y => (x - y) will be always negative. Not possible.
Thus, x and y are both positive.

Sufficient.

The correct answer is C.
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by clawhammer » Sat Nov 27, 2010 5:27 am
Rahul@gurome wrote:First go through the basics, Strengthen your concepts and then go for the shortcuts. If your concepts are clear, you'll never make a wrong assumption.


Statement 2: (x/y) > 1
Again this implies any one of the following two cases,
  • (1) Both of them are positive and x > y
    (2) Both of them are negative and x < y
Not sufficient.
Thanks Rahul.

Clearly this part about abt statement 2 was something I didn't remember. If you gave me x/y = 1. i would have definitely noticed both can be + or -. But I must learn to treat inequalities like equations and remember the basics!

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by tomada » Sun Nov 28, 2010 6:31 pm
.a.a.
Last edited by tomada on Fri Dec 17, 2010 12:08 pm, edited 1 time in total.
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by beat_gmat_09 » Sun Nov 28, 2010 7:37 pm
tomada wrote:I'm a bit confused by this one. Maybe someone can help me understand where I'm erring in my reasoning.

If I let X= -3 and Y= -3.5, the first equation is satisfied: 2(-3) - 2(-3.5) = -6 -(-7) = +1.

Then, the second equation is satisfied because (-3)/(-3.5) > 1
(alternative way of saying this is that -3 > -3.5)

Can someone explain how this isn't a viable scenario?
-3/-3.5 = -3/(-7/2) = +6/+7 < 1
x/y > 1 from statement 2.

Hope this helps.
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.aa...a

by tomada » Sun Nov 28, 2010 8:02 pm
a..a...a
Last edited by tomada on Fri Dec 17, 2010 12:12 pm, edited 2 times in total.
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by beat_gmat_09 » Sun Nov 28, 2010 8:39 pm
tomada wrote:Unfortunately, that doesn't help, because -3/-3.5 > 1. I realize that a negative number divided by a negative number is a positive number, so you're saying that -3/-3.5 = 3/3.5. However, when doing that, you need to change the direction of the inequality sign. We know that 3 < 3.5. However, -3 > -3.5. So, when you go from -3/-3.5 to 6/7, you need to change the direction of the inequality sign.

I hope that helps.
Were you asking for a explanation or are yourself giving one (in earlier post and now) :)
In the above case you need not change the direction of sign.
Remember when the numerator and denominator both are -ve the result of division is always +ve, so there is no question of multiplying the inequality sign with negative number and to change the direction of inequality sign.
your numbers i.e. -3 and -3.5 do not fit the solution (when both the statements are combined)
because statement 2 does not pass as 6/7 < 1 and the reason it is less than 1 is aforementioned (i.e. num and deno when -ve result is +ve, inequality sign needn't be changed)
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by prateek_guy2004 » Thu Sep 01, 2011 1:49 pm
I understand statement 1 and 2 are not sufficient but why C.

Can you please explain how to conclude that both X and y are positive.....
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by knight247 » Fri Sep 02, 2011 8:09 am
1. 2x-2y=1

Lets pick numbers for this one.
Let x=2 y=1.5
2(2)-2(1.5)=4-3=1 Condition Satisfied. Also x and y are +ve

Now, let x=-1.5 and y=-2
2(-1.5)-2(-2)=-3+4=1 Condition is still satisfied but x and y are -ve. This statement gives conflicting answers hence INSUFFICIENT

2. x/y>1
Meaning either both are positive and x>y eg 5>3
Or
Both are negative and |x|>|y| eg -5<-3 yet -5/-3>1. Again we get conflicting values of x and y hence INSUFFICIENT.

Combining both we have that both x and y have the same signs. i.e. either both are +ve or both are -ve. And if both are -ve then |x|>|y|. Again by plugging number we can eliminate the possibility that they are both negative. If both are negative and |x|>|y| then 2x-2y=1 will always be negative. Try x=-8 and y=-2. Also, try x=-3 y=-2. So the possibility of both being negative is ruled out. Now use our original values x=2 y=1.5. The condition is met. Hence C

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by prateek_guy2004 » Fri Sep 02, 2011 11:51 am
Hi knight247

Thanks mate good approach..was just confused about the concluding both statements together...but thanks for explaining .....

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