BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Arithmetic mean

Expert replies
by Winner2013 » Thu Oct 10, 2013 5:53 am
Committee X and Committee Y , which have no common members, will combine to form Committee
Z . Does Committee X have more members than Committee Y ?

(1) The average (arithmetic mean) age of the members of Committee X is 25.7 years and the
average age of the members of Committee Y is 29.3 years.

(2) The average (arithmetic mean) age of the members of Committee Z will be 26.6 years.

Answer is C
Join the discussion
Source: — Data Sufficiency |

by theCodeToGMAT » Thu Oct 10, 2013 6:05 am
Please use spoiler for Hiding the Answers

N1 = X
N2 = Y

N1/N2 = (M2-M)/(M-M1) [weighted average formula]

To find: N1/N2 > 0

Statement 1:
M1 = 25.7
M2 = 29.3
We don't have "M"
INSUFFICIENT

Statement 2:
M = 26.6
INSUFFICIENT

Combining..
We have M,M1 & M2.
SUFFICIENT

Answer [spoiler]{C}[/spoiler]
R A H U L
Join the discussion

by mevicks » Thu Oct 10, 2013 6:13 am
Let the Nos. of members be x, y, z
We know that x + y = z

Q: Is x > y ?

St1: Just gives the average ages of x and y. INSUFFICIENT.
St2: Only average age of Z is known. INSUFFICIENT

St1 + St2: Becomes a Weighted Average Problem.

If the proportion of x and y was equal this would be the scenario:
x_____________Mid___________y
25.7_________27.5___________29.3

Since the final average is 26.6 (avg of z) we can answer that x > y
x_____________Mid___________y
25.7___26.6___27.5__________29.3

[spoiler]Answer : C[/spoiler]

Here x pulls the average down (for more info) and is less than 27.5


Regards,
Vivek

p.s: Please hide your answers using the "spoiler" tag
Join the discussion

by Brent@GMATPrepNow » Thu Oct 10, 2013 6:19 am
Winner2013 wrote:Committee X and Committee Y , which have no common members, will combine to form Committee Z. Does Committee X have more members than Committee Y?

(1) The average (arithmetic mean) age of the members of Committee X is 25.7 years and the
average age of the members of Committee Y is 29.3 years.

(2) The average (arithmetic mean) age of the members of Committee Z will be 26.6 years.

Target question: Does Committee X have more members than Committee Y?

Statement 1: The average (arithmetic mean) age of the members of Committee X is 25.7 years and the average age of the members of Committee Y is 29.3 years.
No way to determine which committee has more people.
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: The average (arithmetic mean) age of the members of Committee Z will be 26.6 years.
No way to determine which committee has more people.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
IMPORTANT CONCEPT: If there are 2 populations (A and B) and A's population is greater than B's population, then the average for the COMBINED population will be closer to A's average than to B's average.

Committee X has an average age of 25.7 years
Committee Y has an average age of 29.3 years
If the two committees had the same population, then the combined committee (Z) would have an average age of 27.5 [since (25.7 + 29.3)/2 = 27.5]

In actuality, the COMBINED committee has an average age of 26.6 years. Since 26.6 is closer to 25.7 (committee X's average) than to 29.3 (committee Y's average), we can conclude that committee X must have more people
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Aside: for more information on weighted averages, you can watch this free GMAT Prep Now video: https://www.gmatprepnow.com/module/gmat- ... ics?id=805

Answer = C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Winner2013 » Thu Oct 10, 2013 7:02 am
Thank you all.

Brent, thank you for helping me understand the concept as well. Your inputs are always very helpful !
Join the discussion