What is the greatest distance between any two points on a cylinder with radius 4 and height 8?
a) 10
b) sqrt128
c) 12
d) 6
e) 7
a) 10
b) sqrt128
c) 12
d) 6
e) 7
Just the interior diagonal whose ends are one diameter apart. So, the hypotenuse of the right triangle formed by the height of the cylinder and the diameter of same.
Both are 8 so square root of 8^2 + 8^2 = 128^(1/2)
