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Selecting door

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by talaangoshtari » Wed Jul 01, 2015 12:17 pm
3C1 = 3, so in 3 ways we can choose a door. Since the doors for entering and leaving the room are the same, the answer is 3
Last edited by talaangoshtari on Wed Jul 01, 2015 10:38 pm, edited 1 time in total.
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by Ian Stewart » Wed Jul 01, 2015 1:38 pm
It's not clear what the question means, because the wording is not precise. I'd assume that we can use the same door to enter and leave, and that it matters which door we use to enter, and which we use to leave. Under those assumptions, we have 3 choices for the enter door, and 3 for the exit door, so 3*3 = 9 choices in total.
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by nikhilgmat31 » Fri Jul 03, 2015 12:23 am
I think question is asking to choose 2 doors out of 3 in a room.
1 to enter & 1 to leave

A,B,C are three doors & we need to choose 2 doors where order matters. - so answer is 3!/1! = 6

A,B
B,A
A,C
C,A
A,B
B,A
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by nikhilgmat31 » Thu Jul 09, 2015 1:28 am
if we can use wither same of different doors to enter/exit.

number of ways is 3*3 = 9
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by timur12 » Sun Sep 04, 2016 10:05 pm
Assuming different doors to be used:
The problem can be divided in 2 steps.
1) First select the door(assuming doors can be differentiated based on something).

3 ways

2) Then choose which door to use for entry and exit.

2 ways

Total ways 3*2 = 6 ways
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by Matt@VeritasPrep » Thu Sep 15, 2016 8:04 pm
It all depends on whether you can use the same door to enter and leave. The GMAT would specify, I think, so this isn't the best question.
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