Order

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Order

by pullagurla » Thu Sep 02, 2010 10:33 pm
If r = 0.345, s = (0.345)^2, and t = 0 345^1/2 . , which of
the following is the correct ordering of r, s, and t ?
(A) r < s < t
(B) r < t < s
(C) s < t < r
(D) s < r < t
(E) t < r < s

Explain the basic principle !
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by Rahul@gurome » Thu Sep 02, 2010 10:42 pm
Solution:
If 0 < n < 1, n^2 < n < sqrt(n).
For example let n = 0.25.
So n^2 =.0625 and sqrt(n) = 0.5.
Now 0.0625 < 0.25 < 0.5.

Hence (0.345)^2 < 0.345 < sqrt(0.345).
Or s < r < t.

The correct answer is (D).
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