varun289 wrote:234. If n and y are positive integers and 450y=n^3, which of the following must be an integer?
I Y/(3 * 2^2 * 5)
II Y/(3^2 * 2 * 5)
III Y/(3 * 2 * 5^2)
A None
B I only
C II only
D III only
E I, II, and III
It almost always helps to find the prime factorization in these question types where we ask whether a certain rational expression is an integer.
450y = n^3
2*3*3*5*5*y = n^3
For 2*3*3*5*5*y to be a cube, we need the number of 2's, 3's and 5's in the prime factorization to each be divisible by 3.
So, for example, 2*2*2*2*2*2*3*3*3*5*5*5 = (2*2*3*5)^3
For 2*3*3*5*5*y to be a cube, it must be the case that the prime factorization of y includes
at least two additional 2's, one additional 3 and one additional 5.
So, y =
2*2*3*5*(other possible numbers)
Now check the option.
I. Must y/(3 * 2^2 * 5) be an integer?
Plug in y to get:
2*2*3*5*(other possible numbers)/(3 * 2^2 * 5)
= some integer
II. Must y/(3^2 * 2 * 5) be an integer?
Plug in y to get:
2*2*3*5*(other possible numbers)/(3^2 * 2 * 5)
= 2*(other possible numbers)/3
Not necessarily an integer
III. Must y/(3 * 2 * 5^2) be an integer?
Plug in y to get:
2*2*3*5*(other possible numbers)/(3 * 2 * 5^2)
= 2*(other possible numbers)/5
Not necessarily an integer
Answer:
B
Cheers,
Brent
