B166418 wrote:When a tree was first planted ,it was 4 feet tall ,and the height of the tree increased by a constant amount each year for the next 6 years .At the end of 6th year ,the tree was 1/5 taller than it was end of the 4th year .By how many feet did the height of tree increase each year
A) 3/10
B) 2/5
C) 1/2
D) 2/3
E) 6/5
Height of tree on day 0 = 4
Let d = the height increase each year
Height of tree at the end of the 1st year = 4+d
Height of tree at the end of the 2nd year = 4+d+d = 4+2d
Height of tree at the end of the 3rd year = 4+d+d+d = 4+3d
Height of tree at the end of the 4th year = 4+d+d+d+d = 4+4d
Height of tree at the end of the 5th year = 4+d+d+d+d+d = 4+5d
Height of tree at the end of the 6th year = 4+d+d+d+d+d+d = 4+6d
We are told that 4+6d is 1/5 greater than 4+4d
In other words 4+6d = (4+4d) + 1/5(4+4d)
or 4+6d = 6/5(4+4d)
Multiply both sides by 5 and (to eliminate fractions) and solve for d to get d=2/3
The answer is
D
Cheers,
Brent