BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

last digits

Expert replies
by shashank.ism » Mon Feb 08, 2010 7:22 am
What are the last two digits of 7^2008?

a) 21
b) 61
c) 01
d) 41
e) 81
Last edited by shashank.ism on Mon Feb 08, 2010 11:19 am, edited 1 time in total.
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.
Join the discussion
Source: — Problem Solving |

by harsh.champ » Mon Feb 08, 2010 7:26 am
shashank.ism wrote:What are the last two digits of 72008?

a) 21
b) 61
c) 01
d) 41
e) 81
Apparently it is 08...:P:)...Did you miss anything over here shashank??
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Join the discussion

by ajith » Mon Feb 08, 2010 11:07 am
shashank.ism wrote:What are the last two digits of 72008?

a) 21
b) 61
c) 01
d) 41
e) 81
Thats not fun; what are the last two digits of 7^2008 would have been fun {which requires modulo operations and I think is out of scope again}
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by harsh.champ » Mon Feb 08, 2010 11:19 am
ajith wrote:
shashank.ism wrote:What are the last two digits of 72008?

a) 21
b) 61
c) 01
d) 41
e) 81
Thats not fun; what are the last two digits of 7^2008 would have been fun {which requires modulo operations and I think is out of scope again}
Well,this is also okay.
Now,7^1 = 07 [ last 2 digits are written on the RHS of =]
7^2 = 49
7^3 = 43(343)
7^4= 01 (2401)
7^5 = 07
So,we see that after every 4 no.s the same last 2 digits are repeated.[spoiler]
As, 2008 is divisible by 4 so the abs. is 01. (C)[/spoiler]

Ajith,if you carefully note,rest of the 4 options are bogus.If any option would have been 49 or 43 or 07 then the question would have been difficult.
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Join the discussion

by ajith » Mon Feb 08, 2010 11:55 am
harsh.champ wrote: Ajith,if you carefully note,rest of the 4 options are bogus.If any option would have been 49 or 43 or 07 then the question would have been difficult.
Well you cant say that, it is easily found out that last digit of 7^2008 is 1 so all the options have 1 as the last digit. It would have been easier had they kept the options as u have mentioned
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by money9111 » Mon Feb 08, 2010 1:27 pm
harsh.champ i got as far as 7^4 then i'm like.. yeah i'm doing something wrong... not thinking to myself "just see if it begins repeating somewhere." i wouldn't have known to then divide 2008 by 4, to get to 01 being the answer. I will now in the future though
My goal is to make MBA applicants take onus over their process.

My story from Pre-MBA to Cornell MBA - New Post in Pre-MBA blog

Me featured on Poets & Quants

Free Book for MBA Applicants

Join the discussion