BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

remainder

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 232
Joined: Fri Jun 18, 2010 7:09 amFollowed by: 2 members
Thanked: 1 times
by ruplun » Fri May 06, 2011 9:07 pm
if w,x,y and z are the digits of the 4 digit number N ,a positive integer , what is the remeiander when N is divided by 9?

(1) w+x+y+z=13
(2)N+5 is divisible by 9
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Legendary Member
Posts: 1112
Joined: Sat Feb 26, 2011 11:16 amFollowed by: 49 members
Thanked: 77 times

by atulmangal » Fri May 06, 2011 11:14 pm
ruplun wrote:if w,x,y and z are the digits of the 4 digit number N ,a positive integer , what is the remeiander when N is divided by 9?

(1) w+x+y+z=13
(2)N+5 is divisible by 9
IMO D

(1) u can solve by putting some no's or if u know about the divisibility test of 9

for a no to be divisible by 9...the sum of digits should be a multiple of 9..for ex 72, 99, etc

try to see this pattern

72 --> 7+2 = 9....9/9 => R = 0 72/9 => R = 0
73 --> 7+3 = 10...10/9 => R = 1 73/9 => R = 1
74 --> 7+4 = 11...11/9 => R = 2 74/9 => R = 2

similarly for no N...the sum of digits is 13 always that means 13/9 => R = 4 will always be the remainder..

Op B...clearly 5 will always be the remainder

Hence Op D is correct
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members
Thanked: 85 times

by clock60 » Fri May 06, 2011 11:18 pm
hi ruplun
the answer looks like D
(1)w+x+y+z=13=9+4. remaider 4, it is possible to check simple numbers to verify
say ab=20, what remaider if divisible by 9
20=2*9+2. and 2+0=2=9*0+2
85=9*9+4, and 8+5=13=9*1+4
53=9*5+8, and 5+3=8=9*0+8
the same hols in the problem
the remaider will be the same as you divide the the sum of the digits by 9
so 1 st suff
(2)n+5 is divisible by 9
5 is not divisible by 9, and it comes that n is also not. but n+5 is divisible
thus the sum of remaiders resulting from division by 9 both 5 and must be divisible by 9
i mean
5=9*0+5, and the only remaider the if added to 5 will give sum that is divisible by 9 is 4
so 2 st also suff
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members
Thanked: 85 times

by clock60 » Fri May 06, 2011 11:20 pm
atulmangal wrote:
ruplun wrote:if w,x,y and z are the digits of the 4 digit number N ,a positive integer , what is the remeiander when N is divided by 9?

(1) w+x+y+z=13
(2)N+5 is divisible by 9
IMO D

(1) u can solve by putting some no's or if u know about the divisibility test of 9

for a no to be divisible by 9...the sum of digits should be a multiple of 9..for ex 72, 99, etc

try to see this pattern

72 --> 7+2 = 9....9/9 => R = 0 72/9 => R = 0
73 --> 7+3 = 10...10/9 => R = 1 73/9 => R = 1
74 --> 7+4 = 11...11/9 => R = 2 74/9 => R = 2

similarly for no N...the sum of digits is 13 always that means 13/9 => R = 4 will always be the remainder..

Op B...clearly 5 will always be the remainder
Hence Op D is correct
hi atul
you got right answer
but are you dead sure about st 2?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1112
Joined: Sat Feb 26, 2011 11:16 amFollowed by: 49 members
Thanked: 77 times

by atulmangal » Fri May 06, 2011 11:32 pm
clock60 wrote:
atulmangal wrote:
ruplun wrote:if w,x,y and z are the digits of the 4 digit number N ,a positive integer , what is the remeiander when N is divided by 9?

(1) w+x+y+z=13
(2)N+5 is divisible by 9
IMO D

(1) u can solve by putting some no's or if u know about the divisibility test of 9

for a no to be divisible by 9...the sum of digits should be a multiple of 9..for ex 72, 99, etc

try to see this pattern

72 --> 7+2 = 9....9/9 => R = 0 72/9 => R = 0
73 --> 7+3 = 10...10/9 => R = 1 73/9 => R = 1
74 --> 7+4 = 11...11/9 => R = 2 74/9 => R = 2

similarly for no N...the sum of digits is 13 always that means 13/9 => R = 4 will always be the remainder..

Op B...clearly 5 will always be the remainder
Hence Op D is correct
hi atul
you got right answer
but are you dead sure about st 2?
Hey thanks for pointing that...remainder will be 4 always
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1