Hi, I got this question wrong, does anyone know how to work out the right answer? Any help is greatly appreciated!
Combining both equations :
1: (3r+2-s) (4r+9-s)=0
2: (4r-6-s) (3r+2-s) =0
we have one of these factors from each could be zero.
so if we take (3r+2-s)=0=>3r+2=s
and similarly (4r-6-s)=0=>4r-6=s
now 3r+2=4r-6=>r=8 ans s=26 so we can say the values of r ans are satisfying the equation y=3x+2 (here x is r and y is s)
Any better way of solution could be much appreciated !
