BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Cant form the equation

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 429
Joined: Wed Sep 19, 2012 11:38 pmFollowed by: 4 members
Thanked: 6 times
by [email protected] » Tue Aug 06, 2013 6:36 pm
The line represented by the equation y=4-2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (-4, 1)
(B) (-2, 2)
(C) (0, 1)
(D) (0, -1)
(E) (2, 0)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Tue Aug 06, 2013 7:25 pm
The line represented by the equation y = 4 - 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (-4, 1)
(B) (-2, 2)
(C) (0, 1)
(D) (0, -1)
(E) (2, 0)

OA:D
Just draw a picture of what is being described. A perpendicular bisector:

-- intersects at the midpoint
-- forms a right angle

Here's my rudimentary drawing:

Image

Looking at the drawing above, we can see that P must have a negative y-coordinate.
Only answer choice D works.

The correct answer is D.

Check here for a similar problem:

https://www.beatthegmat.com/grockit-toug ... 74452.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 90
Joined: Wed Jun 26, 2013 10:55 pmFollowed by: 1 member
Thanked: 11 times

by macattack » Tue Aug 06, 2013 11:51 pm
For those who are not into drawing here is how I approach such problems:
The perpendicular bisector bisects the line RP at its midpoint. Call the point I. Now choosing P we need to make sure that I's coordinate verify the equation of the bisector since it is the intersection point.
x(i)=(x(p)+x(r))/2 y(i)=(y(p)+y(r))/2
Plug in the different answer choice into the above equation get the coordinate of i and then plug them into the equation of the bisector and see if they verify that equation!
Only answer D does the job.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 490
Joined: Thu Jul 04, 2013 7:30 amFollowed by: 5 members
Location: Chennai, India
Thanked: 83 times

by Uva@90 » Sat Aug 10, 2013 10:12 pm
[email protected] wrote:The line represented by the equation y=4-2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?

(A) (-4, 1)
(B) (-2, 2)
(C) (0, 1)
(D) (0, -1)
(E) (2, 0)
shibsriz,
An another method,
As we know that when two lines are perpendicular then product of the slope of two lines is -1
So from the given statement, y=4-2x,the slop of the line is -2.
So, -2*m = -1 => m = 1/2

We know the one point of the second line i.e. (4,1)
So (y2-y1)/(x2-x1)=m => (y2-1)/(x2-4) = 1/2 Substitute options given.
The only option that matches is [spoiler]D(0,-1)[/spoiler]

Regards,
Uva
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1