working with powers from gmat prep

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by harshavardhanc » Wed Apr 28, 2010 3:53 am
cat er ina wrote:can someone help me with this headeache here pleaseee?

2^X-2^x-1=3(2)^13 what is the value of x?

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Thank you :)
I think there is a typo in the question.

Anyway,

here's a link that'll help you :

https://www.beatthegmat.com/post219532.html#219532
Regards,
Harsha

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by Stuart@KaplanGMAT » Wed Apr 28, 2010 11:21 am
cat er ina wrote:can someone help me with this headeache here pleaseee?

2^X-2^x-1=3(2)^13 what is the value of x?

CORRECT ANS. 15
Thank you :)
Hi,

please make sure that you parse your questions with brackets to make things clear.

To generate the answer you provided, the question should read:

If 2^x - 2^(x-2) = 3*(2^13), then what is the value of x?

There are a few ways we could approach this - backsolving is certainly one approach (please always include both the source of your question and the answer choices), but we have no choices.

We can also use logic/algrebra to solve. We see that the coefficient on the right side is "3" and that we're dealing with powers of 2. What two powers of 2 subtract to 3? 4 and 1. So, we have to be factoring out a 2^2 out of the first term (to get the 4) and nothing out of the second term (to get the 1).

Accordingly, we have:

4(2^13) - 1(2^13) = 3(2^13)

Now we simply equate either the first or second term of our derivation to that of the original equation. So, we could solve for x either with:

2^x = 4(2^13)
2^x = 2^2 * 2^13
2^x = 2^15
x = 15

or

2^(x-2) = 2^13
x-2 = 13
x = 15
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