BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Quadratic

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Mon Mar 19, 2007 6:23 pm
Location: Cambridge, MA

by mindruna » Thu Aug 09, 2007 11:42 am
Is the answer C?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 103
Joined: Wed May 30, 2007 6:17 amFollowed by: 1 member

by tanyajoseph » Fri Aug 10, 2007 8:39 am
The answer is II only . Can u please explain in detail? Thanx
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 277
Joined: Sun Jun 17, 2007 2:51 pmFollowed by: 1 member
Location: New York, NY
Thanked: 6 times

by givemeanid » Fri Aug 10, 2007 10:01 am
x +ve, y +ve

I. Let's assume sqrt(x+y)/2x > 1/sqrt(x+y)
sqrt(x+y) > 0 since x and y are +ve
sqrt(x+y)*sqrt(x+y) > 2x
x+y > 2x
y > x
But x could be > y and our assumption falls flat.
NOT TRUE.


II. Lets assume (sqrt(x) + sqrt(y))/(x+y) > 1/sqrt(x+y)
sqrt(xx + xy) + sqrt(xy + yy) > x+y

Since x and y are +ve, sqrt(xx + xy) > x and sqrt(xy + yy) > y
TRUE.


III. Lets assume (sqrt(x) - sqrt(y))/(x+y) > 1/sqrt(x+y)
Right side is always +ve
However, if y > x, left side is -ve. So, we cannot assume this to be true.
NOT TRUE.


II only. Answer is C.
So It Goes
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1