If n is a positive integer and r is the remainder when (n-1)(n+1) is divided by 24, what is the value of r?

1). n is not divisible by 2

So n is an odd number

n=1 - 0
n=3 - 8
n=5 - 0

INSUF ( I did not catch the n=3 case before )

2). n is not divisible by 3

n=1 - 0

n=2 - 3

Insuf

Together we know that n can not be 3 and n will be an ODD number

1, 5, 7, 11 and for all of these number the remainder will be 0

Choose C

Logitech could you please explain me about this ??

1). n is not divisible by 2

So n is an odd number

n=1 - 0
n=3 - 0
n=5 - 0

So We will always get 0 as a remainder SUF

How is this sufficient ??

yalanand wrote:Logitech could you please explain me about this ??

1). n is not divisible by 2

So n is an odd number

n=1 - 0
n=3 - 0
n=5 - 0

So We will always get 0 as a remainder SUF

How is this sufficient ??

If n is a positive integer and r is the remainder when (n-1)(n+1) is divided by 24, what is the value of r?

So we are asked to find the remainder. And in the first statement we all have 0 as the remainder when the number is divided by 24.

For example n=5

(n-1)(n+1) = 4x6=24 divided by 24 , remainder is 0

Now looking at my previous post, I realized that the only ODD number that will leave a different remainder is n=3

2x4=8 and when is divided by 24 , the remainder is 8

So it seems like A can not be sufficient because of the n=3 case.

Let's say what other will have to say :roll: