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vivek.kapoor83
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DS ques-- gud 1
Source: Beat The GMAT — Problem Solving |
why E ?
and for checking the condition in ques we have to prove by considering that after removal of mod, it can be -ve and +ve
like
mod (x-y) > mod(x-z)
removing mod.
x-y > x-z
and -(x-y) > -(x-z)
do, we need to prove both the equation correct ? as after removing mod, you can have 2 values.(-ve & +ve) and mode for both will be same.
and for checking the condition in ques we have to prove by considering that after removal of mod, it can be -ve and +ve
like
mod (x-y) > mod(x-z)
removing mod.
x-y > x-z
and -(x-y) > -(x-z)
do, we need to prove both the equation correct ? as after removing mod, you can have 2 values.(-ve & +ve) and mode for both will be same.
Is mod (x-y) > mod(x-z)
a. mod y > mod z
b. x<0
It is a DS ques
a> it gives a relation in y and z, nothing about x..............insufficient
b> only tells us about x<0, nothing on y and z.................insufficient
together
we know x<0
lyl>lzl
lets take x=-10
y=-4, z=3
lx-yl>lx-zl...................
l-10-(-4)l = 6
l-10-3l=13....................6<13
so lx-yl<lx-zl
all same, just changing y, y=4
lx-yl=14......now 14>13
here lx-yl>lx-zl.........................insufficient
so IMO: E
whats OA?
a. mod y > mod z
b. x<0
It is a DS ques
a> it gives a relation in y and z, nothing about x..............insufficient
b> only tells us about x<0, nothing on y and z.................insufficient
together
we know x<0
lyl>lzl
lets take x=-10
y=-4, z=3
lx-yl>lx-zl...................
l-10-(-4)l = 6
l-10-3l=13....................6<13
so lx-yl<lx-zl
all same, just changing y, y=4
lx-yl=14......now 14>13
here lx-yl>lx-zl.........................insufficient
so IMO: E
whats OA?
vivek, just a small thing was missedvivek.kapoor83 wrote:why E ?
and for checking the condition in ques we have to prove by considering that after removal of mod, it can be -ve and +ve
like
mod (x-y) > mod(x-z)
removing mod.
x-y > x-z
and -(x-y) > -(x-z)
do, we need to prove both the equation correct ? as after removing mod, you can have 2 values.(-ve & +ve) and mode for both will be same.
when you remove mod it could be +ve or -ve, right
now we have an inequality here lx-yl > lx-zl
so it should result in four posiibilities
1. .......+(x-y) > +(x-z)........................both +ve
2. .......+(x-y) > -(x-z).........................lhs +ve, rhs -ve
3. .......-(x-y) > +(x-z).........................lhs -ve, rhs +ve
4. .......-(x-y) > -(x-z).........................both -ve
hope this helps
It's pretty simple:
Question asks the if the distance between X and Y is greater than the distance between X and Z.
A) tells you Y has a greater magnitude than Z. No info about X. Not suff.
B) tells you nothing about Y and Z. Obviously not sufficient.
A and B put together tell you Y could be negative or positive.
Y=-5 X=-2 and Z=3 satisfies both the conditions giving you a No as answer.
Y=5 X=-2 and Z=3 satisfies both the conditions giving you a YES.
So, E.
Question asks the if the distance between X and Y is greater than the distance between X and Z.
A) tells you Y has a greater magnitude than Z. No info about X. Not suff.
B) tells you nothing about Y and Z. Obviously not sufficient.
A and B put together tell you Y could be negative or positive.
Y=-5 X=-2 and Z=3 satisfies both the conditions giving you a No as answer.
Y=5 X=-2 and Z=3 satisfies both the conditions giving you a YES.
So, E.
