how do i solve this?

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by pemdas » Mon Sep 03, 2012 3:45 pm
grandh01 wrote:If x≠2, then = 3x^2(x-2)-x+2/x-2
(A) 3x 2 − x + 2
(B) 3x 2 +1
(C) 3x 2
(D) 3x 2 −1
(E) 3x 2 − 2
I guess you mean this notation [(3x^2)*(x-2)-x+2]/(x-2)
simplify -(x-2)/(x-2) to get -1. Then 3x^2(x-2)/(x-2)=3x^2 and obtain 3x^2-1
d
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by GMATGuruNY » Mon Sep 03, 2012 5:00 pm
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Let x=0.
Then ( 3x²(x-2)-x+2 ) / (x-2) = ( 0-0+2 ) / (0-2) = -1.
Now we plug x=0 into the answers to see which yields our target of -1.
A quick scan reveals that only D works:
3x²-1 = 0-1 = -1.

The correct answer is D.
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