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Please confirm the OA

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Source: — Data Sufficiency |

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by Rahul@gurome » Wed Jun 23, 2010 9:49 pm
The question is x/3+3/x>2 or x^2 + 9 > 6x or x^2 - 6x + 9 = 0 or (x - 3)^2 > 0 or is x > 3?
(1) says x < 3 so x cannot be greater than 3. So the answer to the main question is No.
(1) is SUFFICIENT.

(2) x > 1 does not imply positively that x > 3 also. x may or may not be greater than 3. So, (2) is NOT SUFFICIENT.

The correct answer is (A).
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by kvcpk » Wed Jun 23, 2010 10:19 pm
Rahul@gurome wrote:The question is x/3+3/x>2 or x^2 + 9 > 6x or x^2 - 6x + 9 = 0 or (x - 3)^2 > 0 or is x > 3?
Hi Rahul,

(x - 3)^2 > 0 need not mean that x>3.. because, x=1 also staisfies it.
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by kvcpk » Wed Jun 23, 2010 10:34 pm
ssgmatter wrote:Is
x/3+3/x>2?

(1) x < 3
(2) x > 1

I think OA is B in this case.Please confirm
I believe that OA is C.

a + 1/a >=2 for all positive a.

here a = x/3. so for all positive values of x/3 the statement holds true.

Let us put values and see.. clearly A is not answer.. because if x is -ve value, x/3+3/x will never be >2

So A, D are out.

if x>1, then x=3 will give value 2. and x=2 will give value greater than 2.

So B is also Out.

I belive answer should be C.

For any value between 1 and 3 it satisfies the equation..
Last edited by kvcpk on Wed Jun 23, 2010 10:57 pm, edited 1 time in total.
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by ssgmatter » Wed Jun 23, 2010 10:41 pm
Rahul@gurome wrote:The question is x/3+3/x>2 or x^2 + 9 > 6x or x^2 - 6x + 9 = 0 or (x - 3)^2 > 0 or is x > 3?
(1) says x < 3 so x cannot be greater than 3. So the answer to the main question is No.
(1) is SUFFICIENT.

(2) x > 1 does not imply positively that x > 3 also. x may or may not be greater than 3. So, (2) is NOT SUFFICIENT.

The correct answer is (A).
OA given is C

But I still think it should be B.

I approach this question by taking values

STMT 1. x<3....check the inequality using values of x<3 Insufficient
stmt2...Take any value of x>1 and the given inequality is satisfied....please check at your end...Sufficient

So B
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by kvcpk » Wed Jun 23, 2010 10:58 pm
ssgmatter wrote: But I still think it should be B.

I approach this question by taking values

STMT 1. x<3....check the inequality using values of x<3 Insufficient
stmt2...Take any value of x>1 and the given inequality is satisfied....please check at your end...Sufficient

So B
Hi ssgmatter,

Try taking value x=3
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by ssgmatter » Thu Jun 24, 2010 12:26 am
kvcpk wrote:
ssgmatter wrote: But I still think it should be B.

I approach this question by taking values

STMT 1. x<3....check the inequality using values of x<3 Insufficient
stmt2...Take any value of x>1 and the given inequality is satisfied....please check at your end...Sufficient

So B
Hi ssgmatter,

Try taking value x=3
Thankyou Man for highlighting that

That is called doing questions in hurry and missing out like this

Yes the OA is C now.....I am done with this
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by sumanr84 » Thu Jun 24, 2010 3:19 am
ssgmatter wrote:Is
x/3+3/x>2?

(1) x < 3
(2) x > 1

I think OA is B in this case.Please confirm
(1) x < 3
when x = 1, x/3+3/x = (1/3 + 3 ) > 2, YES
when x = -1, x/3+3/x = (-1/3 - 3 ) = - (1/3 + 3 ) > 2 , NO

So, St 1 -- Not sufficient

(2) x > 1
when x=3, x/3+3/x = 2 > 2 , NO
When x = 9 , x/3+3/x = 3 + 1/3 > 2 , YES

So, St 2 -- Not sufficient

Taken together, all values of x b/w 1 and 3 satisfy the inequality. Hence -- C
I am on a break !!
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by Rahul@gurome » Thu Jun 24, 2010 4:22 am
Right, the OA is (C). Statement (1) also is NOT SUFFICIENT, thanks for pointing that out.
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by kvcpk » Thu Jun 24, 2010 4:37 am
Rahul@gurome wrote:Right, the OA is (C). Statement (1) also is NOT SUFFICIENT, thanks for pointing that out.
You are welcome :)
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by outreach » Thu Jun 24, 2010 10:23 am
C is correct
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