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10 < a < b < c < 20

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by sanju09 » Mon May 10, 2010 12:36 am
If a, b, and c are three consecutive odd integers such that 10 < a < b < c < 20 and if b and c are prime numbers, what is the value of a + b?
(A) 24
(B) 28
(C) 30
(D) 32
(E) 34
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by harshavardhanc » Mon May 10, 2010 12:58 am
sanju09 wrote:If a, b, and c are three consecutive odd integers such that 10 < a < b < c < 20 and if b and c are prime numbers, what is the value of a + b?
(A) 24
(B) 28
(C) 30
(D) 32
(E) 34
[spoiler]
Odd integers in that range : 11, 13, 15, 17, and 19. As a,b, and c are consecutive odd integers, they must be 15,17, and 19, for b and c are prime.

Hence a+b = 15+17 = 32. IMO D.[/spoiler]
Regards,
Harsha
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