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If \(x\) is a number such that \(x^2 + 2x - 24 = 0\) and \(x^2 + 5x - 6 = 0,\) then \(x =\)

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Re: If \(x\) is a number such that \(x^2 + 2x - 24 = 0\) and \(x^2 + 5x - 6 = 0,\) then \(x =\)

by Scott@TargetTestPrep » Sun May 03, 2020 5:31 am
Gmat_mission wrote: ↑
Sun Apr 26, 2020 11:46 am
 If \(x\) is a number such that \(x^2 + 2x - 24 = 0\) and \(x^2 + 5x - 6 = 0,\) then \(x =\)

A. -6
B. -4
C. -3
D. 3
E. 6

[spoiler]OA=A[/spoiler]

Source: Magoosh
We can solve each equation and look for the value of x that satisfies both equations. Or we can set the left hand side of the equations equal to each other since they are both equal to 0. Let’s do the latter since it’s easier:

x^2 + 2x - 24 = x^2 + 5x - 6

2x - 24 = 5x - 6

-3x = 18

x = -6

Answer: A

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