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How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?
A. 8
B. 12
C. 60
D. 118
E. 120
The OA is C.
Ways in which 3 seats out 5 can be selected = 5C3
Ways in which 3 people can be arranged in 3 seats = 3!
Total ways of arrangement = 5C3*3!
= 5*4! / 2*6
= 10*6
= 60.
Has anyone another suggestion about how to solve this PS question? Thanks!
A. 8
B. 12
C. 60
D. 118
E. 120
The OA is C.
Ways in which 3 seats out 5 can be selected = 5C3
Ways in which 3 people can be arranged in 3 seats = 3!
Total ways of arrangement = 5C3*3!
= 5*4! / 2*6
= 10*6
= 60.
Has anyone another suggestion about how to solve this PS question? Thanks!















