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by vivek.kapoor83 » Fri Jan 02, 2009 3:53 am
If on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.

40%

55%

35%

30%

im getting ans as 50%



2.Two cars are 15 kms apart. One is turning at a speed of 50kmph and the other at
40kmph . How much time will it take for the two cars to meet?


3/2 hours

3/5 hours

2/3 hours

1/2 hours
.

im gettin ans as 1/6 hrs
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Source: — Problem Solving |

by ronniecoleman » Fri Jan 02, 2009 4:10 am
on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.

40%

55%

35%

30%


S selling price
x be cost price

so (75 /100 * s ) / x = 25

3s = x


now

(90/100 * s )/ x =

(3s/x )* 30

30

hence 30 %



Two cars are 15 kms apart. One is turning at a speed of 50kmph and the other at
40kmph . How much time will it take for the two cars to meet?


3/2 hours

3/5 hours

2/3 hours

1/2 hours

cars are moving in same direction!!! i guess
Admission champion, Hauz khaz
011-27565856
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by vittalgmat » Thu Jan 15, 2009 2:25 am
If on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.


The question looks ambiguous to me..
Pls correct me, if I am wrong.

Here are the ways that I could interpret.

1. Original price = 100. They give a 25% discount. They earn 25% profit.
Here is 25% profit on 100?
OR
25% profit on 75?

2. "If they now give 10% discount"
Does it mean 10% discount on 100 (ie instead of giving a 25% discount)
OR
is it another 10% discount on 75 ??


Pls let me know your thoughts.
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by 4meonly » Fri Jan 16, 2009 12:39 pm
ronniecoleman wrote:on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.

S selling price
x be cost price

so (75 /100 * s ) / x = 25
3s = x
now
(90/100 * s )/ x =
(3s/x )* 30
30
hence 30 %
(75 /100 * s ) / x = 25
why 25? Discounted price divided by cost will be 1,25
(75 /100 * s ) / x = 1.25
3s/4x = 5/4
20x=12s
5x=3s
s=5x/3

9s/10 = 9*5x/10*3 = 3x/2 this is price with 10% discount
3x/2x = 3/2. So, 50% profit
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by 4meonly » Fri Jan 16, 2009 12:45 pm
ronniecoleman wrote: Two cars are 15 kms apart. One is turning at a speed of 50kmph and the other at
40kmph . How much time will it take for the two cars to meet?

3/2 hours
3/5 hours
2/3 hours
1/2 hours
cars are moving in same direction!!! i guess
aha... and what car is 15 km ahead?
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by Mr2Bits » Fri Jan 16, 2009 12:50 pm
ronniecoleman wrote:on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.

40%

55%

35%

30%


S selling price
x be cost price

so (75 /100 * s ) / x = 25

3s = x


now

(90/100 * s )/ x =

(3s/x )* 30

30

hence 30 %



Two cars are 15 kms apart. One is turning at a speed of 50kmph and the other at
40kmph . How much time will it take for the two cars to meet?


3/2 hours

3/5 hours

2/3 hours

1/2 hours

cars are moving in same direction!!! i guess

Can you explain how you came to this? Im not seeing x = 3s out of this original equation

so (75 /100 * s ) / x = 25

3s = x
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by truplayer256 » Fri Jan 16, 2009 1:21 pm
on an item a company gives 25% discount, they earn 25% profit. If they now
give 10% discount then what is the profit percentage.

The mindset that I had when I solved this problem was as follows:

The company paid x dollars on an item and they are selling it for y dollars.
.75y= 1.25x
A 10% discount would mean:

.90y=(?)x

?=1.5 or a 50 percent profit... I'm kind of surprised that it isn't an answer choice..
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by 720dreaming » Fri Jan 16, 2009 1:32 pm
One more vote for 50%...
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by gaggleofgirls » Fri Jan 16, 2009 2:07 pm
I see a ratio here for the first problem.

for 75%x the company receives 25%x as profit

So, for 90%x, what profit will the company receive?

75:25 = 90:x
25/75 = x/90
1/3 = x/90
3x=90
x=30
so 30%

For the second question, if the cars are 15kms apart and traveling along the same path AND the faster car is behind the slower car, then it will take 3/2 hour (one and one half hour) for the car traveling 10k/h faster to make up the 15km difference.
However, that is a lot to infer from the question, which needs to be less ambiguous.

-Carrie
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