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Function question

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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Function question

by Lookingfor700GMAT » Wed Mar 10, 2010 11:58 am
Can you please explain this question?

For all numbers x such that x does NOT equal 1. if g(x)=x^2+2/x-1 then (1/g(2)) (1/g(x)) = ?

I thought that the answer is x^2+2/6(x-1). However the answer is in fact x-1/6(x^2+2)

I came to the answer - x^2+2/6(x-1) via the following, please can someone point out what I did wrong

I squared 2 then added 2 then divided by 1 (x is 2 - 1) which is 6/1 then I multiplied that with 1/x^2/x-1
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by mohit11 » Wed Mar 10, 2010 9:31 pm
(1/g(2)) (1/g(x)) = ?


g(2) = 6/2-1 = 6 1/g(2) = 1/6

g(x) = x^2+2/x-1 1/g(x) = x-1 /x^2+2


(1/g(2)) (1/g(x)) = 1/6 * x-1 /x^2+2 = x -1 /6x^2 + 12
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