Drawing the lines as neha24 described is the easiest method to solve this problem. But if you are having problem with that approach then you can follow this mathematical approach but this is way more time consuming.
Let us assume the equations of L1 and L2 are y = ax + b and y = px + q, respectively.
Hence, slopes of the lines are a and p and y-intercept of the lines are b and q, respectively.
As the lines are non-parallel, we know that a ≠b.
We need to determine whether, a < p or not.
Statement 1: Let us assume that the intersection point is (X, Y), where X > 0 and Y > 0.
Hence, Y = aX + b and Y = pX + q
Solving these two equations, X = (q - b)/(a - p) and Y = (aq - bp)/(a - p)
Hence, (q - b)/(a - p) > 0 and (aq - bp)/(a - p) > 0
In other words, (q - b), (a - p) and (aq - bp) are of same sign.
Clearly this is not enough to conclude whether a < p or not.
Not sufficient
Statement 2: b < q
Clearly this is not enough to conclude whether a < p or not.
Not sufficient
1 & 2 Together: Now we know that, (q - b) > 0
Hence, (a - p) is positive too.
Hence, a > p
Sufficient
The correct answer is C.
