Value of integer

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Value of integer

by Sak32 » Mon Nov 18, 2013 7:53 am
What is the value of integer n?

1) n(n+1)=6
2) 2^2n= 16

What is baffling me is that in 2) the answer should be Not Sufficient because logically it could be either 2 or -2. Why didnt we consider the -2 as well?? Both powers yield 16 since they are even. The answer was deemed sufficient with 2 only.

Its an OG question.
Last edited by Sak32 on Mon Nov 18, 2013 8:08 am, edited 1 time in total.
Source: — Data Sufficiency |

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by Brent@GMATPrepNow » Mon Nov 18, 2013 8:03 am
Sak32 wrote:What is the value of integer n?

1) n(n+1) = 6
2) 2^(2n) = 16
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Target question: What is the value of integer n?

Statement 1: n(n+1) = 6
Expand to get: n² + n = 6
Set equal to zero: n² + n - 6 = 0
Factor: (n + 3)(n - 2) = 0
So, n = -3 or n = 2
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: 2^(2n) = 16
2^(2n) = 16
Rewrite 16 as 2^4 to get: 2^(2n) = 2^4
So, we can conclude that (2n) = 4, in which case n must equal 2
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = B

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by Brent@GMATPrepNow » Mon Nov 18, 2013 8:12 am
Sak32 wrote: What is baffling me is that in 2) the answer should be Not Sufficient because logically it could be either 2 or -2. Why didnt we consider the -2 as well?? Both powers yield 16 since they are even. The answer was deemed sufficient with 2 only.
Let's try n = 2 and n = -2

n = 2: 2^(2n) = 2^(4) = 16 PERFECT
n = -2: 2^(2n) = 2^(-4) = 1/16 nope

I believe that you're thinking of a different rule that refers to situations in which the BASE (not the exponent) is negative.

So for example, 4^2 = 16 and (-4)^2 = 16

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by Sak32 » Mon Nov 18, 2013 8:13 am
Thanxx

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by Mathsbuddy » Fri Nov 22, 2013 9:22 am
16 = 2^4
So 2n = 4 and n = 2

Check with 1) 2(2+1) = 6 OK

Answer: n=2

If n = -2, them 2^(2 * -2) = 2^-4 = 1/16 NOT RIGHT

Statement 1 ALONE: n^2 + n - 6 = (n + 3)(n - 2) = 0
so n = 2, -3

Answer: n=2