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Is the product st negative?

Expert replies
by gmattesttaker2 » Sat Aug 24, 2013 10:54 pm
Hello,

Can you please help with the following question?


OA: C

My approach was as follows:

1) No info. about t - Insuff.

2) ( s - 4 )/(t - 3) = 1

s - 4 = t - 3
s - t = 1

4 - 3 = 1 (st < 0 - No)
-3 - (-4) = 1 (st < 0 - No)
0 - ( -1 ) = 1 (st < 0 - No)

I was just wondering what scenario would make 2 insufficient? Thanks a lot - Sri
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Source: — Data Sufficiency |

by GMATGuruNY » Sun Aug 25, 2013 4:07 am
Is the product st negative?

(1) s^2 - s < 0
(2) (s-4)/(t-3) = 1

OA is C. I don't understand how B cannot be sufficient.
Stmt 2 says S=t+1, which means one of them is 0 so st=0 OR both positive OR both negative. In all these cases st is positive or 0 which means it is not negative. This should be sufficient. What am I missing here? Can some one please give me an example.
Thanks.
Statement 1: s² < s.
s must be a positive fraction between 0 and 1.
In other words:
0 < s < 1.
No information about t.
INSUFFICIENT.

Statement 2: (s-4)/(t-3) = 1
s-4 = t-3
s = t+1.
If t=0 and s=1, then st is not negative.
If t=-1/2 and s=1/2, then st is negative.
INSUFFICIENT.

Statements 1 and 2 combined:
Substituting s=t+1 into 0 < s < 1, we get:
0 < t+1 < 1
-1 < t < 0.
Since s is positive and t is negative, st is negative.
SUFFICIENT.

The correct answer is C.

An important take-away:
It is important to note how a problem is RESTRICTED and how it ISN'T.
Since there is no requirement here that s and t be integers, we must consider FRACTIONS.
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by ani781 » Sun Aug 25, 2013 6:25 am
I have approached this way :
1) Only information for s is given , not sufficient. Eliminate A and D.
2) s-4 = t-3
It follows that depending on the value of s , t can be + ve or -ve.
e.g. if s = 5 , t > 0
But if , s = -2 then t < 0.... So eliminate B.

Combining,
From s^2-s < 0 => s(s-1)<0 .. Two cases possible.
Case A: s< 0 and s-1 >0 = > s> 1 ... so s cant be both <0 and >1 ; So not possible
Case B : s>0 and s-1 <0 => 0<s<1 which implies s > 0.

So, from 2nd statement :
s-4 = t-3
=> s - 1 = t
=> t < 0 , as 0<s <1

So clearly, s> 0 and t <0 ... Hence correct answer is C.
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by [email protected] » Sun Aug 25, 2013 12:54 pm
Hi gmattesttaker2,

These types of DS question are based on Number Properties, so it sometimes helps to think about what would give you a YES answer and what would give you a NO answer.

The question asks: Is (s)(t) negative?

So, here are the options:
(s) (t) Result
+ + No
- - No
0 any No
any 0 No
+ - Yes
- + Yes

With this limited set of options, you can now go LOOKING for the exception, instead of hoping to accidentally stumble across is by randomly testing values. Since you figured out that s - t = 1, the only way to get a "one positive, one negative" solution is if you use fractions.

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