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What percent of x is 3/4?

Expert replies
by pappueshwar » Mon Mar 19, 2012 7:25 am
What percent of x is 3/4?

(1) x = .5y
(2) y = 10

OA IS C

IMO A, i took the question stem "what percent" as Y i.e Y/100 * X = 3/4
Hence used A to prove.

since stmtn 2 does not give the value of X i thought its not sufficient.
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Source: — Data Sufficiency |

by Mike@Magoosh » Mon Mar 19, 2012 8:57 am
Hi, there. I'm happy to help with this.

Prompt: What percent of x is 3/4?

Notice there are two variable in this prompt ---- the percentage (call it p), for which the prompt asks, and the variable x. They are related by the equation:

x*p = 3/4

(Assume p is written in decimal form.) Right now, we have one equation and two unknowns.

Statement #1: x = .5y

This statement introduces an another equation with another variable, so now we have two equations with three unknowns. We still can't solve.

If we plug in:

x*p = 3/4 ---> 0.5y*p = 3/4 (still can't solve for p)

Notice, pappueshwar, that
(i) you don't get an equation with both x and y in it at the same time
(ii) even if you could determine that y is the percent, which is not, then that would not be an answer to the prompt question, because a DS prompt, unless otherwise stated, is always looking for a numerical answer.

Statement #1 is insufficient.

Statement #2: y=10

Of course, this, by itself, is useless. We want to solve x*p = 3/4 for p, and this statement gives the value of a variable that does not appear in this prompt equation. Statement #2 is insufficient.

Combined Statements #1 & #2
Now, we have x = .5y and y = 10.
Plug y into the first equation, and we get x = 5.
Now, go back to x*p = 3/4 and plug x=5 into this ---> 5p = 3/4 ----> p = 3/20 = 0.06, or 6%

Combined, the statements allow us to come up with a definitive numerical answer to the prompt question. Combined, they are sufficient. Answer = C

Does that make sense? Here's a practice PS question with percents and variables

https://gmat.magoosh.com/questions/34

When you submit your answer to that question, the following page will have a full video explanation.

Let me know if you have any further questions.

Mike :)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
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