swerve wrote:
Square ABCD is perfectly inscribed in the circle pictured above. If minor arc AD measure 2Ï€, what is the approximate area of the shaded region?
A. 110
B. 72
C. 36
D. 18
E. 9
The OA is
D.
Please, can any expert explain this PS question for me? I have many difficulties to understand why that is the correct answer. Thanks.
Since minor arc AD is 1/4 of the circle, the circumference of the circle is 4 x 2Ï€ = 8Ï€.
Now we can find the radius of the circle using the circumference formula C = 2Ï€r:
8Ï€ = 2Ï€r
4 = r
Thus, the area of the circle is π * 4^2 = 16π and the diameter of circle = 8. Since the diameter of circle = the diagonal of the square and the diagonal of the square = side√2, we have:
8 = side√2
8/√2 = side
Thus, the area of the square is (8/√2)^2 = 64/2 = 32.
So, the area of the shaded region is approximately 16π - 32 = 16(π - 2). Since π is approximately 3.14, we have 16(3.14 - 2) = 16(1.14), which is approximately 18.
Answer: D
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