Whats the source of this question?
To me,
2x = b. If b < 1 then x < 1/2. So effectively x < 3.

D seems right but the question doesn't. :roll:

Got it from Kaplan.

My argument in this question is that b is given less than 1 i.e. b is negative or 0.

So for
,in 2x-b=0 x has to be negative for the equation to be 0.that means if b<0 as given x is also <0.

Th only option that proves this is B and hence i chose it.

As for the answer given we can clearly prove that for x=2 b=4; which proves the given b<0 wrong.

Please help me with this.

Mia09 wrote:If b<1 and 2x-b =0, which of the following must be true?

A)x>-1
B)x<-2
C)x=2
D)x<3
E)x>3

OA is D.Please explain your answer

b<0: b could be 0.5, 0, -0.2, -10

Take the above values for b and substitute it in the above equation to get 2x and x value.

b 0.5 0 -0.2 -10
2x 0.5 0 -0.2 -10
x 0.25 0 -0.1 -5

In the above values, x value is below 0.25

A. x>-1 is wrong. x has a value of even -5
B. x<-2; Wrong; x has a value of 0.25.
C. x = 2; wrong; x has several values.
D. x<3; Correct. All the x values are below 3.
E. x>3; Wrong. All the x values are less than 3.

Hope it helps.

Mia09 wrote:Got it from Kaplan.

My argument in this question is that b is given less than 1 i.e. b is negative or 0.

So for
,in 2x-b=0 x has to be negative for the equation to be 0.that means if b<0 as given x is also <0.

Th only option that proves this is B and hence i chose it.

As for the answer given we can clearly prove that for x=2 b=4; which proves the given b<0 wrong.

Please help me with this.

What makes you think b is an integer? It could be 0.5. Then x doesn't have to be negative.

If b<1 and 2x-b =0, which of the following must be true?

A)x>-1
B)x<-2
C)x=2
D)x<3
E)x>3

First here, I would solve for x in terms of b. This reduces the amount of calculation you will have to do later.

x = b/2

If b<1, then x<1/2.

D) is the only answer that satisfies x < 1/2 completely.