VJesus12 wrote:If S = {0, 4, 5, 2, 11, 8}, how much greater than the median of the numbers in S is the mean of the numbers in S?

(A) 0.5
(B) 1.0
(C) 1.5
(D) 2.0
(E) 2.5

Ordering the numbers from least to greatest we have:

0, 2, 4, 5, 8, 11

So the median of S is (4 + 5)/2 = 4.5.

The mean of S is (0 + 2 + 4 + 5 + 8 + 11)/6 = 30/6 = 5.

So the mean is 0.5 greater than the median.

Answer: A

The median of a set with even number of elements is the average of two middle element when arranged in ascending order.
median;
S= {0,2,4,5,8,11}
median= $$\frac{\left(4+5\right)}{2}=\frac{9}{2}=4\ \frac{1}{2}$$

The mean of the set= $$\frac{\left(0+2+4+5+8+11\right)}{6}=\frac{30}{6}=5$$
The difference = 5 - 4.5= 0.5 $$\frac{\left(0+2+4+5+8+11\right)}{6}=\frac{30}{6}=5$$
$$Therefore,\ the\ mean\ is\ 0.5\ greater\ than\ the\ median.\ Hence\ option\ A\ is\ accurate$$