X=kt?
st(1) t<0, then k<0 too and kt>0 -hence X will be positive and to the right of t, Sufficient;
st(2) k<1, t can be +ve OR -ve OR even 0, Not Sufficient
IOM A
Tagne wrote: 1. On a number line, if the number k is to the left of the number t, the product kt to the right of t?
a. T < 0
b. K < 1
|x|>|y| ?
squaring both parts, we get x^2>y^2 ? explanation when mode is positive number - squared numbers will be positive and comparable
st(1) x^2>y^2 Sufficient
st(2) x>y Not Sufficient, compare x=2, y=-3 |x|<|y| BUT x>y. It can be also x=2 and y=-1, |x|>|y| And x>y
IOM A
Tagne wrote: 2. is IxI > IyI ?
a. X^2 > Y^2
b. X > Y
