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khurram
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The question below is one of the toughest I have seen.
Total bags are 453. Each bag contains at least one of the following: raisin, almonds and peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain only peanuts. The number of bags that contain almonds is 20 times the number of bags that contain only raisins and peanuts. The number of bags that contain only peanuts is 1/5 the number of bags that contain only almonds. 210 bags contain almonds. How many bags cotain only one kind of item
Ans is 320.
This is how I have solved.
bags only Raisins= 10 times bags contain only peanuts.
bags only Almonds= 20 times the bags that contain raisins and peanuts.
bags that contain only peanuts=1/5 the number of bags that contain only almonds.
r=10p
r+P=y name Y
A=20(r+P) or same as (20Y)
p=1/5 A or 1/5 (20Y) or 4y
so P =4y
A =20Y
R=10p or 40Y
so 64Y What Then.
How do you get 320.
Thanks
Khurram
Total bags are 453. Each bag contains at least one of the following: raisin, almonds and peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain only peanuts. The number of bags that contain almonds is 20 times the number of bags that contain only raisins and peanuts. The number of bags that contain only peanuts is 1/5 the number of bags that contain only almonds. 210 bags contain almonds. How many bags cotain only one kind of item
Ans is 320.
This is how I have solved.
bags only Raisins= 10 times bags contain only peanuts.
bags only Almonds= 20 times the bags that contain raisins and peanuts.
bags that contain only peanuts=1/5 the number of bags that contain only almonds.
r=10p
r+P=y name Y
A=20(r+P) or same as (20Y)
p=1/5 A or 1/5 (20Y) or 4y
so P =4y
A =20Y
R=10p or 40Y
so 64Y What Then.
How do you get 320.
Thanks
Khurram












