Paul's average bowling score for a series was...

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BTGmoderatorLU: Moderator; Posts: 2505; Joined: Sun Oct 15, 2017 1:50 pm; Followed by:6 members

Paul's average bowling score for a series was...

by BTGmoderatorLU » Sat Oct 28, 2017 8:19 am

Paul's average bowling score for a series was 164 and Dave's was 158. If each of them bowled 4 games, how much greater was Paul's total score for the series than Dave's score?

(A) 6
(B) 12
(C) 18
(D) 24
(E) It cannot be determined from the information given.

The OA is D.

I need help to solve this PS question. Can any expert explain it, please? Thanks.

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Source: Beat The GMAT — Problem Solving | Sat Oct 28, 2017 8:19 am

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by [email protected] » Sat Oct 28, 2017 10:56 am

Hi LUANDATO,

There are a couple of different ways to handle the 'math' in this question (and some take a bit longer than others). The 'shortcut' here is that you can determine the difference in TOTAL scores by simply comparing the averages and then multiply by the number of games.

Since Paul's average score was 164 and Dave's average score was 158, Paul beat dave by an average of 6 points EACH game. Since they each bowled 4 games, the difference in TOTAL scores for each would be (6)(4) = 24 points.

Final Answer: D

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Rich

Contact Rich at [email protected]

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by Scott@TargetTestPrep » Tue Nov 12, 2019 7:17 pm

BTGmoderatorLU wrote:Paul's average bowling score for a series was 164 and Dave's was 158. If each of them bowled 4 games, how much greater was Paul's total score for the series than Dave's score?

(A) 6
(B) 12
(C) 18
(D) 24
(E) It cannot be determined from the information given.

The OA is D.

I need help to solve this PS question. Can any expert explain it, please? Thanks.

Since sum = average x quantity, Paul's total score was 164 x 4 and Dave's total score was 158 x 4.

Thus, Paul's total score was 164 x 4 - 158 x 4 = 4(164 - 158) = 4 x 6 = 24 points greater than Dave's.

Answer: D

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